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Vinil7 [7]
3 years ago
12

A current-carrying wire is bent into a circular loop of radius R and lies in an xy plane. A uniform external magnetic field B in

the +z direction exists throughout the plane of the loop. The current has the magnitude of I and it is deirected counterclockwise when observing from positive z axis.What is the magnetic force exerted by the external field on the loop?
Express your answer in terms of some or all of the variables I, R, and B
Physics
1 answer:
Ilya [14]3 years ago
8 0

Answer:

 F = 2π I R B

Explanation:

The magnetic force is described by the equation.

      F = q v x B = i L  x B

Where i is the current, L is a vector that points in the direction of the current (length) and B is the magnetic field.

This equation can be used in scalar form and the direction of the force found by the right hand ruler, the thumb goes in the direction of L, the fingers extended in the direction of B and the palm of the hand indicates the direction of the force if the load is positive

     F = i L B sin θ

In this case the wire is in the xy plane and the z-axis field whereby they are perpendicular, θ = 90º and sin 90 = 1

     F = i L B

The loop length is

    L = 2π R

    F = i 2π R B

    F = 2π I R B

The force is in the loop

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Sedbober [7]

Answer:A the two wire will attract each other

Explanation:

When current is flowing in a wire it is surrounded by magnetic field whose direction can be given by right hand thumb rule.

If current is in direction of your thumb then wrapping of fingers will give the direction of magnetic field.

If two wires with current in same direction flows then the combined  magnetic field will be constructive in nature and thus they attract each other.

force on second wire due to first wire is

F_{21}=I_2\vec{L_2}\times B_1 which will be towards the first wire

3 0
4 years ago
Two charges that are 1 meter apart repel each other with a force of 2 N. If the distance between the charges is increased to 2 m
Savatey [412]

Answer:

b) 0.5 N

Explanation:

From coulomb's law,

F = kq'q/r².................... Equation 1

Where F =force of repulsion between the charges, q' = first charge, q = second charge, r = distance between the charges, k = proportionality constant.

q'q = Fr²/k........................... Equation 2

Given: F = 2 N, r = 1 m, k = 9.0×10⁹ Nm²/C²

Substituting into equation 2

q'q = 2(1)²/(9.0×10⁹)

q'q =  2/9.0×10⁹ C².

If the distance between the charges is increased to 2 meters,

r = 2 m, q'q = 2/9.0×10⁹ C².

Substitute into equation 1

F = 9.0×10⁹(2/9.0×10⁹)/2²

F = 2/4

F = 1/2 = 0.5 N.

The right option is b) 0.5 N

5 0
4 years ago
A 400 kg object is sitting at rest at the top of a hill that is 30.0m high and 80.0m long measured along the hill . If there is
olchik [2.2K]
Theater=sin^-1(30/80)
theater=22
F=400gsin22=150N
F=ma
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a=0.375ms^-2
v^2-u^2=2as
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3 0
4 years ago
An object with an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second squared in the direction
leva [86]

Answer:

6 m/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 4 m/s

Acceleration (a) = 2 m/s²

Distance (s) = 5 m

Final velocity (v) =?

The final velocity of the object can obtained as shown below:

v² = u² + 2as

v² = 4² + (2 × 2 × 5)

v² = 16 + 20

v² = 36

Take the square root of both side.

v = √36

v = 6 m/s

Therefore, the final speed of the object is 6 m/s.

8 0
3 years ago
A skydiver jumps out of a hovering helicopter, so there is no forward velocity. Ignore wind resistance for this exercise. What i
ipn [44]

Answer:

a = g

Explanation:

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3 0
2 years ago
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