Question

A particular sound wave can be graphed using the function y = –3 sin x. Find the period of the function.

Answer 1

F ( x ) 0 - 3 sin x
The period of the function:
T = 2 π / b
f ( x ) = a sin (bx) 
In this case: b = 1.
Therefore: T = 2 π / 1 = 2π
Answer:
A ) Period = 2 π

Answer 2

Answer:

a) period = 2 pi.

Step-by-step explanation:

Given : A particular sound wave can be graphed using the function y = –3 sin x.

To find  :Find the period of the function.

Solution : We have given that y = –3 sin x.

By the sine function : =a sin (bx)  .

Where, a = amplitude,  b = any number ,

Formula of time period = $\frac{2\ pi}{b}$

On comparing the sine function with given function

Here, a = -3 ,  b = 1

Plugging the values in formula of period

Then, Period  =  $\frac{2\ pi}{1}$.

Period =  2 pi

Therefore, a) period = 2 pi.