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2 years ago

15

What is the initial value.

1 answer:

GrogVix [38]2 years ago

6 0

The function shown in the graph is a linear function, for a given linear function, the initial value is obtained at y-intercept. The y-intercept is the point where the graph cuts the y-axis. At this point the value of x is zero. Thus from the graph given, the point x=0 at y=2, hence the initial value is y=2.
Answer: y=2

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Step-by-step explanation:

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Equation of a circle: $(x-h)^2+(y-k)^2=r^2$ where the circle is centered at (h,k) and the radius is r

<u>1) Plug in the given center (7,0)</u>

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<u>2) Plug in the radius (1)</u>

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