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Vladimir79 [104]
3 years ago
5

Please help I am confused I would really appreciate it! I know I need to find a percent but I am not sure how.

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

it should be 90

Step-by-step explanation:

I hope this helps!

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What is the solution to the system of equations graphed below?<br><br> y=x+3<br> y=3x+1
Mademuasel [1]

Answer:

(1, 4)

Step-by-step explanation:

y=x+3

y=3x+1

y=x+3

x+3=3x+1

x=3x-2

-2x=-2

x=1

y=1+3

y=4

8 0
3 years ago
)A bag contains 10 marbles of the same size that are red, yellow, and orange. The probability of picking a red marble is 10%. Th
Cloud [144]

Answer:

Step-by-step explanation:

Its 30%:) because red is 10% and yellow is 60% and there's only 10 marbles which represent 100% so there's 6 yellow marbles and 1 red marble buts that's only 7 so there's 30% left which is 3 marbles left, which has to be orange so the answer is 30%:) hope this helped

5 0
3 years ago
Uh what is 70 times 70 and the square route of 30
almond37 [142]

Answer:

4900

Square Root of 30: 5.47722557505- round it up

Step-by-step explanation:

70x70

7x7=49

add the 2 zeros at the end

4900

4 0
3 years ago
Read 2 more answers
I need some help please !! :)
forsale [732]

Answer: c) 3, 18, 648

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6 0
3 years ago
The digits 4 comma 5 comma 6 comma 7 comma and 8 are randomly arranged to form a​ three-digit number. ​ (Digits are not​ repeate
fenix001 [56]

Answer:

0.1 or 1/10

Step-by-step explanation:

The digits 4, 5, 6, 7 and 8 are randomly arranged to form a three digit number, where the digits are not repeated.

This is question of permutation.

Imagine this sum as; there are 3 boxes(blank spaces for digits) and 5 different fruits(digits) are to be put in these boxes, where a box can hold a maximum of only 1 fruit. The number of such permutations are: ⁵P₃

By formula (a! is factorial a):

ᵃPₙ = \frac{a!}{(a-n)!}

⁵P₃ = \frac{5!}{(5-3)!}

⁵P₃ = \frac{5!}{2!}

⁵P₃ = \frac{5*4*3*2*1}{2*1}

⁵P₃= 60

This is the total count of possible numbers that can be formed.

Now, for a number to be greater than 800 and even; first digit should necessarily be 8. Last digit can be 4 or 6. Using these conditions, there are 6 possibilities. 854, 864, 874, 846, 856, 876 are the numbers.

The probability that number is even and greater than 800 is:

P=\frac{ favorable outcomes}{equally likely possible outcomes}

P=\frac{6}{60}

P=\frac{1}{10}

3 0
3 years ago
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