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3 years ago

Two factors have an estimated product of 10,000. One is a single digit. What two factors can they be. Explain your thinking

Mathematics

1 answer:

RideAnS [48]3 years ago

5 0

It could be 5000 and 2, because 2 is a single digit and the product equals 10000.

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I need this please help

rjkz [21]

Answer:

a) sine
b) 9.8 ft

Step-by-step explanation:

The mnemonic SOH CAH TOA helps you remember the definitions of the trig functions. In particular, the function that involves the Opposite side and the Hypotenuse is the Sine function:

... Sin = Opposite/Hypotenuse

In this problem that means ...

... sin(55°) = x/(12 ft)

Multiplying by 12 ft, we have ...

... (12 ft)·sin(55°) = x ≈ 9.82982 ft ≈ 9.8 ft

7 0

3 years ago

5. A pair of jeans costing

Levart [38]

So $39.50 is the price when you are paying full price, which can be represented by 100%. If you’re paying 25% less, than you are only paying 75% of the original price. Simply multiply $39.50 by 75%(expresses as 0.75) to determine the sale price. 39.50(.75)=29.62 The closest value to that is $29.50, so D is the answer.

6 0

3 years ago

Emily placed her monthly expenses on the budget below to evaluate her excess spending money. Emily's take-home pay is $3,200 eac

Oksana_A [137]

Answer:

Half of the total cost was paid when her braces were put on. The total cost is $3,200. How much will Kelly's parents need to save each month to pay off the ..

Step-by-step explanation:

3 0

3 years ago

If (x+2) is a factor of x^3-6x^2+kx+10, k=

Alja [10]

If a binomial $(x-a)$ is a factor of a polynomial, then $a$ is a root of this polynomial.

$(x+2)=(x-(-2)) \Rightarrow a=-2\\\\
(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\
-8-24-2k+10=0\\
-2k=22\\\
\boxed{k=-11}
$

3 0

3 years ago

The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to

Firdavs [7]

Rewrite the boundary lines y = -1 - x and y = x - 1 as functions of y :

y = -1 - x ==> x = -1 - y

y = x - 1 ==> x = 1 + y

So if we let x range between these two lines, we need to let y vary between the point where these lines intersect, and the line y = 1.

This means the area is given by the integral,

$\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy$

The integral with respect to x is trivial:

$\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy$

For the remaining integral, integrate term-by-term to get

$\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}$

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line y = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

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3 years ago