the line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0

Mathematics

1 answer:

ch4aika [34]3 years ago

7 0

Answer:

y = -x/2 + 1

Step-by-step explanation:

Step 1: find the slope

2x - y - 7 = 0

2x - 7 = y

y = 2x - 7

Equation of a line is y = mx + c

m = slope

m = 2

Note: if two lines are perpendicular to the other, both lines are negative reciprocal of each other

Therefore m = -1/2

Step 2: using a point slope form

y - y1 = m( x - x1)

( 4 , -1)

x = 4

y = -1

y - (-1) = -1/2(x - 4)

y + 1 = -1/2(x - 4)

Open the bracket

y + 1 = -x + 4 / 2

y = (-x + 4) / 2 - 1

LCM = 2

y = -x + 4 - 2 / 2

y = (-x + 2)/2

Separate the two, so as to get the slope and the intercept

y = -x/2 + 2/2

y = -x/2 + 1

The equation of the line is

y = -x/2 + 1

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Brut [27]

Answer:

Step-by-step explanation:

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2) according to the condition the upstream time and the downstream time are the same, it means t₁=t₂=t, where t₁=upstream time and t₂=downstream time;

3) according to the items above it is possible to make up the equation of the upstream travel: t(v-5)=3; ⇒ t=3/(v-5);

4) according to the items above it is possible to make up the equation of the downstream travel: t(v+5)=13; ⇒ t=13/(v+5);

5) if t=3/(v-5) and t=13/(v+5), then

$\frac{3}{v-5} =\frac{13}{v+5}; \ => \ v=8.$