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Anestetic [448]
4 years ago
12

On average, a commercial airplane burns about 3.9 × 10³ mL of gasoline per second. There can be as many as 5.1 × 10³ airplanes i

n the air in the United States at any given time.
About how many milliliters of gasoline are burned per minute by commercial airplanes in flight in the United States?

Enter your answer in the box.
1.2 x 10 to what power?
Mathematics
2 answers:
algol134 years ago
8 0
We use the given data above to calculate the volume of gasoline that is being burned per minute by commercial airplanes. 

Amount burned of 1 commercial airplane = <span>3.9 × 10³ ml of gasoline per second
Number of airplanes = </span><span>5.1 × 10³ airplanes

We calculate as follows:

</span> 3.9 × 10³ ml of gasoline per second / 1 airplane (5.1 × 10³ airplanes)(60 second / 1 min ) = <span>1.2 x 10^9 mL / min</span>
lyudmila [28]4 years ago
5 0

Answer: 1.2x10^9 mL/min

Step-by-step explanation:

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If x=1 and y=2, what is the value of the expression 2x^2-3xy
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2x² - 3xy
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3 years ago
Graph A represents the exponential equation y=4(6) and graph B represents y=6(4). which statements are true about graph a and gr
PtichkaEL [24]

Answer:

Step-by-step explanation:The following statements are true about exponential functions:

-The domain is all real numbers.

- The input to an exponential function is the exponent.

- The base represents the multiplicative rate of change.

The reason why the other two options are wrong are explained below:

The range of exponential functions is not always includes negative numbers; on the contrary, the range is the set of all positive real numbers.

The graph of an exponential function does not have a horizontal asymptote at x = 0; contrarily, the equation of the horizontal asymptote of the graph of is y = 0, which is the x-axis.

4 0
2 years ago
Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

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Afina-wow [57]

Answer:

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