This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Answer:
Step-by-step explanation:
31. D 6.5+8 = 14.5 > 12
32. B -2*5= -10
33. B -2x=6
:)
8600 because 6 is more near to zero than 8.So all the numbers after 6 become 00
Answer:
1. 3/8
2.2/3
That’s the answer. I’m positive!!
Can you add the picture to the question?