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aivan3 [116]
3 years ago
14

In he number 956,783,529, how does the value of the digit 5 in the ten millions place compare to the digit 5 in the hundreds pla

ce?
Mathematics
1 answer:
goblinko [34]3 years ago
3 0
The value of the digit 5 in the ten millions place would be 50,000,000, where the digit 5 in the hundreds place would be 500. Therefore, that would be 5x as much.   (I was having a hard time understanding, please reply and make it more clear, thanks and have a good day! =D)
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The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will
lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

V(t) = 14651(0.81)^{t}

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

V(t) = 14651(0.81)^{t}

(0.81)^t = \frac{V(t)}{14651}

\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}

t\log{(0.81)} = \log{(\frac{V(t)}{14651})}

t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}

(a) $8000

V(t) = 8000

t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7

The car will be worth $1000 after 12.7 years.

5 0
3 years ago
Does anybody know the answer to this
vekshin1

Answer: I believe it's b

Step-by-step explanation:

\pi = 3.14159265...

It is most likely b

4 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Give the digits in the ones place and the tenths place.<br> 86.59
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Digit in ones place- 6
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