What is the force required to move a load 50kg through a distance of 1000cm in 5 seconds

1 answer:

4 0

Based on the 2nd law of motion, the force is a product of the mass and acceleration. We are already given with the mass and the acceleration is calculated by the following equation,
d = Vot + 0.5at²
where d is distance (equal to 1 m), Vo is the initial velocity (equal to 0), a is acceleration, and t is time.

Substituting the known values,
1 m = 0 + 0.5(a)(5 s)²
The value of a is equal to 0.08 m/s².

Now, calculating for force,
F = m x a
F = (50 kg)(0.08 m/s²)
F = 0.32 N

Thus, the force needed to move the load is 0.32N.

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A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan

Nesterboy [21]

Answer:

Compression distance: $d \approx 0.102\,m$

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy ( $K$ ), in joules, at the expense of elastic potential energy ( $U$ ), in joules, and overcoming work losses due to friction ( $W_{l}$ ), in joules:

$K + W_{l} = U$ (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

$\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}$ (2)

Where:

$m$ - Mass of the block, in kilograms.

$v$ - Final velocity of the block, in meters per second.

$\mu$ - KInetic coefficient of friction, no unit.

$g$ - Gravitational acceleration, in meters per square second.

$s$ - Width of the rough patch, in meters.

$k$ - Spring constant, in newtons per meter.

$d$ - Compression distance, in meters.

If we know that $m = 1.2\,kg$ , $v = 2.3\,\frac{m}{s}$ , $\mu = 0.44$ , $g = 9.807\,\frac{m}{s^{2}}$ , $s = 0.05\,m$ and $k = 730\,\frac{N}{m}$ , then the compression distance of the spring is: