Answer:
2.286 km/s²
Explanation:
Since acceleration a = (v - u)/t where u = initial horizontal velocity of ball = 0 m/s (since it starts from rest), v = final horizontal velocity of ball at serve = 73.14 m/s and t = time taken for serve = 32.0 ms = 0.032 s
Substituting the values of the variables into the equation, we have
a = (v - u)/t
a = (73.14 m/s - 0 m/s)/0.032 s
a = 73.14 m/s/0.032 s
a = 2285.625 m/s²
a = 2.285625 km/s²
a ≅ 2.286 km/s²
So, the x - component of the ball's acceleration during the serve is 2.286 km/s²
Answer:
-1.4N
Explanation:
When the distance between A and B is 13.8mm (0.0138m), the force exerted by A on B is 2.65N:
F(A,B) = k*qA*qB/r²
=> 2.65 = k*qA*qB / 0.0138²
=> k*qA*qB = 2.65 * 0.0138²
k*qA*qB = 0.0005046
When the distance between them increases to 19mm (0.019m), the force exerted by A on B becomes:
F(A,B) = k*qA*qB / 0.019²
Given that k*qA*qB = 0.0005046,
F(A,B) = 0.0005046/0.019²
F(A,B) = 1.4N
The force exerted by B on A will be in the opposite direction of the force exerted by A on B, which means that the force exerted by B on A will be:
F(B, A) = -1.4N
Hello!
The slope of the line given by graphing pressure vs 1/Volume at constant temp for one mole of gas will give you the value for nRT from equation PV=nRT
So set nRT=slope and take the constant number mole of gas and the constant temp and solve for R the universal gas constant. You arm for pressure and litters for volume to get R in units of L*atm/mol*k
Hope this helps you! Thanks!!
Yes it does, it helps break down sugars and gives the body energy to keep your system running properly!
Answer:
This is my answer
Explanation:
First convert 150 kPa to Pa:
150 × 1,000 = 150,000.
Next substitute the values into the equation:
force normal to a surface area = pressure × area of that surface.
force = 150,000 × 180.
force = 27,000,000 N.