Speed of the arrow just before it will hit the ground can be calculated by energy conservation
by solving above equation
now this will lodge itself 15 cm into the ground
so after lodging itself to 15 cm the speed of arrow becomes zero
now we will have
Now by Newton's II law net force is given as
Answer:
True
Explanation:
The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.
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The work done in lifting an object to a height of 2 m is equal to two times the weight of the object. W = 2×mg
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Explanation:</h3>
Consider the mass of object to be m kg. The amount of work done to lift an object depends on the force required and the distance to which force is applied. To lift the object to a height of 2 m; Let F be the amount of force applied.
..................(1)
Where,
W=Work done
F= Amount of applied force
h=Height to which object is to be lifted
Applied force is equal to the weight of the object. Therefore,
..............(2)
Where,
m=Mass of the object
g=gravitational acceleration
Substituting (2) in (1), we get
For height = 2 m,
The work done in lifting an object to a height of 2 m is equal to twice the weight of the object.
Answer:
10 m/s
Explanation:
∑F = ma
T = m v² / r
10 N = (1 kg) v² / (10 m)
v = 10 m/s