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Nady [450]
3 years ago
12

A physics student is riding on a train traveling north. Having read about inertia, the student performs an experiment with a gol

f ball. He reaches over the aisle and drops the ball from rest. Instead of hitting the floor directly below the student’s hand, it hits to the north, i.e., forward of that position. Which of the following might be the cause for this to happen?
(A) The train is moving at constant
(B) The train is speeding up. veloeity
(C) The train is slowing down.
(D) Whatever the cause, it cannot be any of the answers given.
Physics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

(C) The train is slowing down.

Explanation:

Since the ball seems to move <em>forward, </em>the train is slowing down. This is because Newton's 1st Law, objects inside the train tend to keep their previous state of movement, that is, the velocity before the train start slowing down, thus appearing to move forward in relation with the train itself.

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Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


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3 years ago
You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction b
adell [148]

Answer:

c

Explanation:

The car travels with centripetal acceleration which is directed to the center of the circle but the velocity is changing since the car faces different direction as it travels in the circular direction. When the friction is zero between the tires of the car and the road, it will continue in the direction of its tangential velocity which will be along a straight-line path in its original direction.

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based on the information in the graph why is energy released during the fission of a uranium (U) nucleus?
frutty [35]

Answer:

B

Explanation:

Nuclear fission is the process of splitting apart nuclei. When nuclei fission energy is released. So much energy is released that there is a measurable decrease in mass, from the mass-energy equivalence. This means that some of the mass is converted to energy.

4 0
3 years ago
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An insulated rigid tank contains 4 kg of argon gas at 450 kPa and 30°C. A valve is now opened, and argon is allowed to escape un
zheka24 [161]

Answer: The final mass of the tank is 2.46kg

Explanation: All shown in the attachment.

Assumptions:

i. Argon is treated as an ideal gas at the specified conditions.

ii. Isentropic relation of ideal gas applies at the given conditions.

4 0
3 years ago
After the ball has left the bat, and while it is traveling upward (at point P in the figure (Figure 1) ), what is the direction
ss7ja [257]
From the moment the ball leaves the bat until the moment the ball hits the ground, its acceleration is 9.8 m/s^2 directed downward. That's the acceleration of gravity.
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