Answer:
False
Explanation:
It is coal-fired power plants that produce mercury, air pollution, and carbon dioxide.
However, nuclear energy produces radioactive waste that must be stored for many years before it can be safely disposed.
Answer:
Copper
Explanation:
Within intermolecular forces, ion-dipole is the strongest, followed by hydrogen bonding, then dipole-dipole, and then London dispersion.
Answer:
(a) 0.25 mol
(b) 0.11 mol
(c) 8.77 mol
Explanation:
(a)
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 1.00 atm
V = Volume of the gas = 6.0 L
T = Temperature of the gas = 298 K
R = Gas constant =
n = number of moles = ?
Putting values in above equation, we get:

(b)
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 0.296 atm
V = Volume of the gas = 6.0 L
T = Temperature of the gas = 200 K
R = Gas constant =
n = number of moles = ?
Putting values in above equation, we get:

(c)
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 30 atm
V = Volume of the gas = 6.0 L
T = Temperature of the gas = 250 K
R = Gas constant =
n = number of moles = ?
Putting values in above equation, we get:

Answer:
K = 4.07x10⁻³
Explanation:
Based on the reaction:
NH₄I(s) ⇄ NH₃(g) + HI(g)
You can define K of equilibrium as the ratio of concentrations of reactants and products, thus:
K = [NH₃] [HI] / [NH₄I]
But, as NH₄I is a solid, is not taken into account in the equilibrium, that means K expression is:
K = [NH₃] [HI]
As the concentrations in equilibrium of the gases is:
[NH₃] = 4.34x10⁻²M
[HI] = 9.39x10⁻²M
Equilibrium constant, K, is:
K = 4.34x10⁻²M * 9.39x10⁻²M
<h3>K = 4.07x10⁻³</h3>
What you are looking for is something from the left side of the periodic table (the metals), combined with something from the right side of the periodic table.
SiCl4 is something from the middle with something on the right. Not the answer.
HCl is a possible answer, but it is not the best one, because Hydrogen can be on both sides. It is not quite as willing to give up its electrons as the answer.
CCl4 has the same problem as A.
The answer is C
Ca is in column 2 just about as far left as you can get.
Cl is in column 17 which is just about as far right as you can get.