Answer:
Cornea >iris>lens >retina
Explanation:
Can't exactly figure out the answer but I think it should look like this
Answer:
i don't know
sorry i would help but i don't know
Explanation:
The molecule is non-polar, because the difference in electronegativity between the two sides of the structure equals 0. The electronegativity difference between O (3.5) and C(2.5) is 1 and also on the other side, cancelling each other.
Answer:
670.68°C
Explanation:
Given that:
volume of water = 50 ml but 1 g = 1 ml. Therefore the mass of water (m) = 50 ml × 1 g / ml = 50 g
specific heat (C) = 4.184 J/g˚C
Initial temperature = 20°C, final temperature = 22°C. Therefore the temperature change ΔT = final temperature - initial temperature = 22 - 20 = 2°C
The quantity of heat (Q) used to raise the temperature of a body is given by the equation:
Q = mCΔT
Substituting values:
Q = 50 g × 4.184 J/g˚C × 2°C = 418.4 J
Since the mass of lead = 5 g and specific heat = 0.129 J/g˚C. The heat used to raise the temperature of water is the same heat used to raise the temperature of lead.
-Q = mCΔT
-418.4 J = 5 g × 0.129 J/g˚C × ΔT
ΔT = -418.4 J / ( 5 g × 0.129 J/g˚C) = -648 .68°C
temperature change ΔT = final temperature - initial temperature
- 648 .68°C = 22°C - Initial Temperature
Initial Temperature = 22 + 648.68 = 670.68°C
Answer:
Final pressure is 1.42atm
Explanation:
Based on Gay-Lussac's law, pressure of a gas is directely proportional to its absolute temperature. The equation of this law is:
P₁T₂ = P₂T₁
<em>Where P is pressure and T is absolute temperature of 1, initial state and 2, final state of the gas.</em>
In the problem, initial conditions are Standard Temperature and Pressure, STP, that are 1 atm and 273.15K.
If the final temperature is 115°C = 388.15K (115°C + 273.15 = 388.15K), using Gay-Lussac's law:
P₁T₂ = P₂T₁
1atmₓ388.15K = P₂ₓ273.15K
1.42atm = P₂
<h3>Final pressure is 1.42atm</h3>
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