When the sound wave returns to the machine, you can measure
how long it took to return.
(You may notice that it's working just like RADAR, which does the
same thing with radio waves instead of sound waves.)
Even if you know how long the sound took to get to the bottom and
return to the top, you can't DO anything with this information if you
don't know the SPEED of the sound through the water. Not only
the inventory of this machine, but anyone who uses it, has to know
the speed of the sound through water in order to use the round-trip
time to calculate the depth.
We will determine the wavelength through the relationship given by the distance between slits, this relationship is given under the function

Here,
m = Number of order bright fringe
= Wavelength
d = Distance between slits
Both distance are the same, then



Rearranging to find the second wavelength




Therefore the wavelength of the light coming from the second monochromatic light source is 550.3nm
A) 3 x 10 ^ 8
b) 3 x 10 ^ 5
c) 3.2 x 10 ^ 7
d) 9.6 x 10 ^ 15 m
e) 9.6 x 10 ^ 17 cm
Answer:
70 revolutions
Explanation:
We can start by the time it takes for the driver to come from 22.8m/s to full rest:

The tire angular velocity before stopping is:

Also its angular decceleration:

Using the following equation motion we can findout the angle it makes during the deceleration:

where
= 0 m/s is the final angular velocity of the car when it stops,
= 114rad/s is the initial angular velocity of the car
= 14.75 rad/s2 is the deceleration of the can, and
is the angular distance traveled, which we care looking for:

or 440/2π = 70 revelutions
Answer:
<u>0.04 °C⁻¹</u>
Explanation:
First, we need to calculate linear expansivity, then after finding that value, we can move on to finding the area expansivity.
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Finding Linear Expansivity :
⇒ α = Final length - Original length / (Original length × ΔT)
⇒ α = 9 - 4 / (4 × 70 - 20)
⇒ α = 5 / 5 × 50
⇒ α = <u>0.02</u>
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Finding Area Expansivity :
⇒ Area Expansivity = 2 × Linear Expansivity
⇒ β = 2 × α
⇒ β = 2 × 0.02
⇒ β = <u>0.04 °C⁻¹</u>