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Valentin [98]
2 years ago
8

Lead has a density of 11. 5 g/cm³. A rectangular block of lead measures 7 cm x 5 cm x 2 cm.

Physics
1 answer:
zubka84 [21]2 years ago
3 0

Answer:

A = 70cm³

B= 805 grams

Explanation:

(a) V = L×B×H

= 7cm × 5cm × 2cm

= 35cm × 2cm

= 70cm³

(b) Mass= volume × Density

= 70cm³ × 11.5g/cm³

=805 grams

I hope this will help you ...

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804 n of force are applied to a 51.7 kg. What is the acceleration that the object experiences?
Andreyy89

We can use Newton II here  (where F=m*a), that F is the net (or resultant) force on the object, m is the mass of the object and a is the acceleration the object experiences.

This means, in this case there would be no friction and absolutely no other force which gives a component in the plane of motion, only then can you assume that F=804N.

Now using F= m*a

804 = 51.7*a

Therefore a = 804/51.7 = 15.55 m/s²


7 0
2 years ago
A 20 g bullet is shot from a 10 kg gun with a velocity of 400 m/s. What
Nady [450]

Answer: -.80m/s

Explanation:

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3 years ago
Would u rather/ have a penny that duplicates its self every day or win 1 million dollars once
arlik [135]

Answer:

1 million dollars once

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8 0
2 years ago
A loop of area 0.250 m^2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.83 × 10-3T· m2, what angle
dangina [55]

Answer:

40.0⁰

Explanation:

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\theta is the angle that the normal to the plane of the loop make with the direction of the magnetic field.

Given

A = 0.250m²

B = 0.020T

\phi = 3.83 × 10⁻³T· m²

3.83 × 10⁻³ = 0.020*0.250cosθ

3.83 × 10⁻³ = 0.005cosθ

cosθ = 0.00383/0.005

cosθ = 0.766

θ = cos⁻¹0.766

θ = 40.0⁰

<em>Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰</em>

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2 years ago
1. If 800 C of electric charge passed through a light bulb in 4 min; what is the mag
9966 [12]

The electric current passing through the bulb would be 3.3A

<u>Explanation:</u>

Given:

Electric charge, q = 800C

Time, t = 4 min

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Electric current, I = ?

We know,

Current  = \frac{Charge}{Time}

On substituting the value we get:

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Thus, the electric current passing through the bulb would be 3.3A

5 0
2 years ago
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