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Montano1993 [528]
3 years ago
6

A sine wave with an rms value of 10.6 v is riding on a dc level of 24 v. what are the maxi- mum and minimum values of the result

ing waveform?
Physics
1 answer:
zheka24 [161]3 years ago
3 0
Amplitude of a sine wave = RMS voltage*Sqrt (2) = 10.6*Sqrt (2) = 14.99 V ≈ 15 V
Therefore,
Range of values of resulting wave = 24+/- Amplitude
Then,
Maximum value of the resulting wave = 24+15 = 39 V
Minimum of the resulting wave = 24-15 = 9 V
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When one member of a binary star system is a black hole, and astronomers detect flickering x-rays coming from the system, where
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When one member of a binary star system is a black hole, and astronomers detect flickering x-rays coming from the system, these x-rays usually coming from a disk of material around the black hole (material that has been pulled from the companion star and is falling toward the black hole).

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For many years, proving the existence of binary black holes was made difficult because of the nature of black holes themselves and the limited means of detection available.

However, in the event that a pair of black holes were to merge, an immense amount of energy should be given off as gravitational waves, with distinctive waveforms that can be calculated using general relativity.

Therefore, during the late 20th and early 21st century, binary black holes became of great interest scientifically as a potential source of such waves and a means by which gravitational waves could be proven to exist. Binary black hole mergers would be one of the strongest known sources of gravitational waves in the universe, and thus offer a good chance of directly detecting such waves.

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8 0
1 year ago
A rocket sled with an initial mass of 3 metric tons, invluding 1 ton of fuel, rests on a level section of track. At t=0, the sol
ELEN [110]

Answer:

v = 719.2 m / s and     a = 83.33 m / s²

Explanation:

This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is

           v - v₀ = v_{e} ln (M₀ / M)

where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket

In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s

            m_fuel = 75 10

            m_fuel = 750 kg

As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is

              M = 3000 -750 = 2250 kg

let's calculate

            v - 0 = 2500 ln (3000/2250)

            v = 719.2 m / s

To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

             Push = v_{e} dM / dt

let's calculate

             Push = 2500  75

             Push = 187500 N

            If we use Newton's second law

             F = m a

             a = F / m

let's calculate

              a = 187500/2250

              a = 83.33 m / s²

7 0
3 years ago
What acceleration occurs if the friction force in #4 is now 4N?
anastassius [24]

Answer:

you a b1tc h

Explanation:

you're not going anywhere in life. mcdonalds hiring $16 an hour where i live.

4 0
2 years ago
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Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.
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that statement is true

a Third class lever applied when the effort place between the load and the fulcrum.

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