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seropon [69]
3 years ago
5

What is 8 m/s - 3 m/s?

Physics
1 answer:
Dima020 [189]3 years ago
3 0

5m/s 8-3 is five so five


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Car A of mass 1200kg traveling at 10m/s , collided in too the back of the car B, which is stationary. Following the collision,.
Nina [5.8K]

Answer:

Car B has a mass of 800 kg.

General Formulas and Concepts:

<u>Momentum</u>

Law of Conservation of Momentum: \displaystyle m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_{f}

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] m₁ = 1200 kg

[Given] v₁i = 10 m/s

[Solve] m₂

[Given] v₂i = 0 m/s

[Given] vf = 6 m/s

<u>Step 2: Solve for m₂</u>

  1. Substitute in variables [Law of Conservation of Momentum]:                       (1200 kg)(10 m/s) + m₂(0 m/s) = (1200 kg + m₂)(6 m/s)
  2. Multiply:                                                                                                             12000 kg · m/s = (1200 kg + m₂)(6 m/s)
  3. Isolate m₂ term:                                                                                                2000 kg = 1200 kg + m₂
  4. Isolate m₂:                                                                                                         800 kg = m₂
4 0
3 years ago
Read 2 more answers
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0
3 years ago
How does the size of the sun compare to the sizes of other stars?
bezimeni [28]
Our sun is quite average when looking at all the stars in the Universe. There are stars that are smaller, like Wolf359, and there are also larger stars, like Betelgeuse. Our sun is essentially right in the middle of the star-size spectrum. 

3 0
3 years ago
Which statement is true regarding the circuit schematic below?
asambeis [7]

C. This is a direct current

<h3></h3><h3>What is schematic Current?</h3>

An electrical schematic is a diagram that shows how all of the wires and components in an electronic circuit are connected.

The ability to read electrical schematics is a really useful skill to have. To start developing your schematic reading abilities,

it’s important to memorize the most common schematic symbols.

Each physical component (i.e resistor, capacitor, transistor) has a unique schematic symbol.

Learn more about Schematic current:

brainly.com/question/15193719

#SPJ1

4 0
2 years ago
the velocity of sound on a particular day outside is 331 meter/sound. what is the frequency of a tone if it has a wavelength 0.6
nataly862011 [7]
The frequency (f) in hertz (1/s) of the sound waves is the quotient when its speed (S) is divided by the wavelength (n). This is mathematically expressed, 
 
                      f = S / n      ;    f = (331 m/s) / (0.6 m)    =   551.67 / s  

Thus, the frequency of the wave is 551.67 Hz.               

6 0
4 years ago
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