The total electric force that these charges exert on a third point charge is 11.9 N and the direction is towards positive y axis.
<h3>
Magnitude of the electric force between the charges</h3>
The force between the first charge and the third charge is calculated as follows;
F₁₃ = kq₁q₃/r₁₃²
F₁₃ = (9 x 10⁹ x 3 x 10⁻⁶ x 4.5 x 10⁻⁶) / (0.1)²
<u>note:</u><em> distance between charge 3.0 μC and Q = 4.5 μC = 0.4 m - 0.3 m = 0.1 m</em>
F₁₃ = 12.15 N
The force between the second charge and the third charge is calculated as follows;
F₂₃ = kq₂q₃/r₂₃²
F₂₃ = (9 x 10⁹ x -3 x 10⁻⁶ x 4.5 x 10⁻⁶) / (0.7)²
<u>note:</u><em> distance between charge -3.0 μC and Q = 4.5 μC = 0.4 m - (-0.3 m) = 0.7 m</em>
<em />
F₂₃ = -0.248 N
<h3>Net force between the charges</h3>
F(net) = F₁₃ + F₂₃
F(net) = 12.15 - 0.248
F(net) = 11.9 N
Thus, the total electric force that these charges exert on a third point charge is 11.9 N and the direction is towards positive y axis.
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Answer:
the angular speed in rad /s is 1675.516 rad/s
Explanation:
The computation is shown below;
The Tachometer's reading is
= 16000 rpm
= 266.67 rps
Now
angular speed ,w = 2 × 
×freq
= 2 × 3.14 × 266.67
= 1675.516 rad/s
Hence, the angular speed in rad /s is 1675.516 rad/s
The same is to be considered by applying the above formula so that the correct speed could arrive
Answer:
Explanation:
Given that,
Small piston Hydraulic piston has an area
A1 = 0.01m²
If the force applied is 250N is applied to the small piston at an area of 0.05 m²
Then,
F2 = 250 N and A2 = 0.05m²
Then, applying pascal principle,
Pressure at small area = pressure are bigger area
P1 = P2
F1 / A1 = F2 / A2
F1 / 0.01 = 250 / 0.05
F1 / 0.01 = 5000
Cross multiply
F1 = 5000 × 0.01
F1 = 50 N
Which is the best example of forces acting in the same direction? a boy lifting his chest off the ground during a pushup. two football players pushing a tackling sled. a person pulling out a garden hose from its reel.
It’s C) because we know that velocity is a vector quantity with direction and speed is only quantity. For example, velocity could be 5 m/s to the east but speed would only be 5 m/s
