Answer:
agear lever or agear stick is the lever that you use to change gear in acar or other vehicle
Explanation:
In the parallel combination, the equivalent resistance is given by :

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

Hence, this is the required solution.
Answer:
» e. Electrons and protons
Explaination :
Electrons are negatively charged and protons are positively charged.
- The neutrons do not have a charge.
The net force acting on the crate is determined as 176 N to the left.
<h3>Net force acting on the crate</h3>
The net force acting on the crate is calculated as follows;
∑F = F1 + F2 + F3 + F4
F(net) = -440y + 176x + 440y - 352x
F(net) = -176 x
The resultant force is pointing in negative x direction.
Thus, the net force acting on the crate is determined as 176 N to the left.
Learn more about net force here: brainly.com/question/14361879
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Answer:
1.
109.6 cm , - 1.74 , real
2.
1.5
Explanation:
1.
d₀ = object distance = 63 cm
f = focal length of the lens = 40 cm
d = image distance = ?
using the lens equation


d = 109.6 cm
magnification is given as


m = - 1.74
The image is real
2
d₀ = object distance = a
d = image distance = - (a + 5)
f = focal length of lens = 30 cm
using the lens equation


a = 10
magnification is given as



m = 1.5