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3 years ago

In a series of undisturbed rock layers where shale lies between sandstone below and limestone above, the ____.

1 answer:

6 0

In a series of undisturbed rock layers where shale lies between sandstone below and limestone above The : A. Limestone is youngest

The basic law Of Geochronology stated that in any undisturbed sequence of rock deposited in layers, the youngest rock will always be placed on top and the oldest on the bottom

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We can reasonably model a 90-W incandescent lightbulb as a sphere 7.0cm in diameter. Typically, only about 5% of the energy goes

Ronch [10]

Answer:

292.3254055 W/m²

469.26267 V/m

$1.56421\times 10^{-6}\ T$

Explanation:

P = Power of bulb = 90 W

d = Diameter of bulb = 7 cm

r = Radius = $\frac{d}{2}=\frac{7}{2}=3.5\ cm$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

The intensity is given by

$I=\frac{P}{A}\\\Rightarrow I=\frac{90}{4\pi 0.035^2}\\\Rightarrow I=5846.50811\ W/m^2$

5% of this energy goes to the visible light so the intensity is

$I=0.05\times 5846.50811\\\Rightarrow I=292.3254055\ W/m^2$

The visible light intensity at the surface of the bulb is 292.3254055 W/m²

Energy density of the wave is

$u=\frac{1}{2}\epsilon_0E^2$

Energy density is also given by

$\frac{I}{c}=\frac{1}{2}\epsilon_0E^2\\\Rightarrow E=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E=\sqrt{\frac{2\times 292.3254055}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E=469.26267\ V/m$

The amplitude of the electric field at this surface is 469.26267 V/m

Amplitude of a magnetic field is given by

$B=\frac{E}{c}\\\Rightarrow B=\frac{469.26267}{3\times 10^8}\\\Rightarrow B=1.56421\times 10^{-6}\ T$

The amplitude of the magnetic field at this surface is $1.56421\times 10^{-6}\ T$

7 0

3 years ago

a girl skateboards with a kinetic energy of 2543.2 J. if the girl and the skateboard have a total mass of 110 kg, what is her sp

zhuklara [117]

Using the definition of kinetic energy, we have:

$E_{c}= \frac{mv^2}{2} \\ 2543.2*2=110v^2 \\ \boxed {v=6.8m/s}$

6 0

3 years ago

The construction of a flat rectangular roof (6.17 m × 5.92 m) allows it to withstand a maximum net outward force of 2.00 × 104 N

Blababa [14]

Answer:

$v_2=29.13\ m/s$

Explanation:

It is given that,

Dimension of the rectangular roof, (6.17 m × 5.92 m)

The maximum net outward force, $F=2\times 10^4\ N$

The density of air, $\rho=1.29\ kg/m^3$

The Bernoulli equation is used to find wind speed of this roof blow outward. It is given by :

$P_1+\dfrac{1}{2}\rho v_1^2=P_2+\dfrac{1}{2}\rho v_2^2$

Here, $v_1=0$ (since air inside the roof is not moving)

$v_2=\sqrt{\dfrac{2(P_1-P_2)}{\rho}}$

Since, $F=(P_1-P_2)A$

$v_2=\sqrt{\dfrac{2F}{\rho A}}$

$v_2=\sqrt{\dfrac{2\times 2\times 10^4}{1.29\times 6.17\times 5.92 }}$

$v_2=29.13\ m/s$

So, the wind speed of this roof blow outward is 29.13 m/s. Hence, this is the required solution.

5 0

4 years ago

A wave has frequency of 10,000 Hz and a wave length of 2cm. Calculate the speed.

Licemer1 [7]

Answer:20,000 m/s

Explanation: the formula is f=v/lambda so you would do 10,000=v/2 and you multiple the 2 to 10,000 since you were originally dividing and you get 20,000 and your unit is m/s

8 0

4 years ago

For a movie scene, an 85.0 kg stunt double falls 12.0 m from a building onto a large inflated landing pad. After touching the la

NeX [460]

Answer:

2785.43N

Explanation:

According to Newton's second law;

$F=\frac{m(v-v_1)}{t_1}..............(1)$