Answer:
Explanation:
energy emitted by source per second = .5 J
Eg = 1.43 eV .
Energy converted into radiation = .5 x .12 = .06 J
energy of one photon = 1.43 eV
= 1.43 x 1.6 x 10⁻¹⁹ J
= 2.288 x 10⁻¹⁹ J .
no of photons generated = .06 / 2.288 x 10⁻¹⁹
= 2.6223 x 10¹⁷
wavelength of photon λ = 1275 / 1.43 nm
= 891.6 nm .
momentum of photon = h / λ ; h is plank's constant
= 6.6 x 10⁻³⁴ / 891.6 x 10⁻⁹
= .0074 x 10⁻²⁵ J.s
Total momentum of all the photons generated
= .0074 x 10⁻²⁵ x 2.6223 x 10¹⁷
= .0194 x 10⁻⁸ Js
b ) spectral width in terms of wavelength = 30 nm
frequency width = ?
n = c / λ , n is frequency , c is velocity of light and λ is wavelength
differentiating both sides
dn = c x dλ / λ²
given dλ = 30 nm
λ = 891.6 nm
dn = 3 x 10⁸ x 30 x 10⁻⁹ / ( 891.6 x 10⁻⁹ )²
= 11.3 x 10¹² Hz .
c )
10 nW = 10 x 10⁻⁹ W
= 10⁻⁸ W .
energy of 50 dB
50 dB = 5 B
I / I₀ = 10⁵ ; decibel scale is logarithmic , I is energy of sound having dB = 50 and I₀ = 10⁻¹² W /s
I = I₀ x 10⁵
= 10⁻¹² x 10⁵
= 10⁻⁷ W
= 10 x 10⁻⁸ W
power required
= 10⁻⁸ + 10 x 10⁻⁸ W
= 11 x 10⁻⁸ W.
Answer:
![2.27\cdot 10^{49}](https://tex.z-dn.net/?f=2.27%5Ccdot%2010%5E%7B49%7D)
Explanation:
The gravitational force between the proton and the electron is given by
![F_G=G\frac{m_p m_e}{r^2}](https://tex.z-dn.net/?f=F_G%3DG%5Cfrac%7Bm_p%20m_e%7D%7Br%5E2%7D)
where
G is the gravitational constant
is the proton mass
is the electron mass
r = 3 m is the distance between the proton and the electron
Substituting numbers into the equation,
![F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N](https://tex.z-dn.net/?f=F_G%3D%286.67259%5Ccdot%2010%5E%7B-11%7D%20m%5E3%20kg%20s%5E%7B-2%7D%29%5Cfrac%7B%281.67262%5Ccdot%2010%5E%7B-27%7Dkg%29%20%289.10939%5Ccdot%2010%5E%7B-31%7Dkg%29%7D%7B%283%20m%29%5E2%7D%3D1.13%5Ccdot%2010%5E%7B-68%7DN)
The electrical force between the proton and the electron is given by
![F_E=k\frac{q_p q_e}{r^2}](https://tex.z-dn.net/?f=F_E%3Dk%5Cfrac%7Bq_p%20q_e%7D%7Br%5E2%7D)
where
k is the Coulomb constant
is the elementary charge (charge of the proton and of the electron)
r = 3 m is the distance between the proton and the electron
Substituting numbers into the equation,
![F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N](https://tex.z-dn.net/?f=F_E%3D%288.98755%5Ccdot%2010%5E9%20Nm%5E2%20C%5E%7B-2%7D%29%5Cfrac%7B%281.602%5Ccdot%2010%5E%7B-19%7DC%29%5E2%7D%7B%283%20m%29%5E2%7D%3D2.56%5Ccdot%2010%5E%7B-19%7DN)
So, the ratio of the electrical force to the gravitational force is
![\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}](https://tex.z-dn.net/?f=%5Cfrac%7BF_E%7D%7BF_G%7D%3D%5Cfrac%7B2.56%5Ccdot%2010%5E%7B-19%7D%20N%7D%7B1.13%5Ccdot%2010%5E%7B-68%7DN%7D%3D2.27%5Ccdot%2010%5E%7B49%7D)
So, we see that the electrical force is much larger than the gravitational force.
The inaccurate measurements must be similar to the other two measurements (ex; 590, 589, 599), but different from the actual volume of water. (Ex; the actual volume is let say.. 100, but you measured 50, 49, 40)
![\underline {\huge \boxed{ \sf \color{skyblue}Answer : }}](https://tex.z-dn.net/?f=%20%5Cunderline%20%7B%5Chuge%20%5Cboxed%7B%20%5Csf%20%5Ccolor%7Bskyblue%7DAnswer%20%3A%20%20%7D%7D)
<u>Given :</u>
![\tt \large {\color{purple} ↬ } \: \: \: \: \: I_{D} = 5mA](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clarge%20%7B%5Ccolor%7Bpurple%7D%20%20%20%20%20%E2%86%AC%20%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20I_%7BD%7D%20%3D%205mA)
![\: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20)
![\tt \large {\color{purple} ↬ } \: \: \: \: \: I_{DSS} = 10mA](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clarge%20%7B%5Ccolor%7Bpurple%7D%20%20%20%20%20%E2%86%AC%20%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20I_%7BDSS%7D%20%3D%2010mA)
![\: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20)
![\tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS(off)} = -6V](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clarge%20%7B%5Ccolor%7Bpurple%7D%20%20%20%20%20%E2%86%AC%20%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20V_%7BGS%28off%29%7D%20%3D%20-6V)
![\: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20)
![\tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS} = {?}](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clarge%20%7B%5Ccolor%7Bpurple%7D%20%20%20%20%20%E2%86%AC%20%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20V_%7BGS%7D%20%3D%20%20%20%7B%3F%7D)
![\: \: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
<u>Let's Slove :</u><u> </u>
![\: \: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
![\: \: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
![\: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20)
Dang dude you are a soldier! Good job