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JulijaS [17]
3 years ago
5

In a scientific experiment, the_

Physics
2 answers:
inysia [295]3 years ago
7 0

C dependent variable because dependent means relying on something else
Svetradugi [14.3K]3 years ago
5 0

The value of a dependent variable changes in response to other changes in a scientific experiment.

Answer: Option C

Explanation:

In the course of going through a scientific experiment, we encounter two types of variables in the calculations,

  • An independent variable
  • The dependent variable

An independent variable doesn’t change in terms of values throughout the experiment and remains constant respective to all the changes whereas dependent variables are affected by the changes in the values of other variables or the modes of experiment.  

The independent variable is termed as the presumed cause and the dependent variable is termed as the presumed effect. The subject of experiment is to find out the exact or relevant values of the dependent variables that can be a person, place, thing or a phenomenon.

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Four solid plastic cylinders all have radius 2.41 cm and length 5.94 cm. Find the charge of each cylinder given the following ad
Paladinen [302]

Answer:

Check explanation

Explanation:

QUICK NOTE: THE QUESTION IS NOT COMPLETE. Although it is not, we can make assumptions, since we only need values for the UNIFORM CHARGE DENSITY.

SO, LET US BEGIN;

To solve this question we are to use the equation (1) below;

Charge,Q = uniform charge density,p × Total area of the cylinder,A ------------------------------------------------------------------------(1).

From the question, we are given radius, R to be 2.41 cm and length, L to be 5.94 cm.

Step one: calculate for the total area of the cylinder, A.

Total area of the cylinder, A= area of the top surface + area of the buttom + area of the curved surface of the cylinder.

Hence, total area of the cylinder,A is;

==> πR^2 + πR^2 + 2πRL. -------------------------------------------------------------------------(2).

Then, total area of the cylinder,A is;

==> (L + R)2πR.

Step two: find the charge of each cylinder.

===> For the first cylinder; we have the uniform charge density to be 35 nC/m^2.

Therefore, the combination of equation (1) and (3) gives;

Charge Q= p × (L + R)2πR...----------------------------(4)

Hence, Q= 35 × [(5.94 + 2.41) 2× 3.143 × 5.94].= 10912.615 coulumb.

====> For the second cylinder, we have a uniform charge density of 50 nC/m^2.

Using equation (4), charge,Q= 15,589.45 Coulumb

=====> For THE third cylinder, the uniform charge density is 600, we make use of equation (4);

Charge,Q= 600×311.789.

Charge,Q= 187,073.4 coulumb.

====> For THE fourth cylinder, the uniform charge density is 750 nC/m^2.., we make use of equation (4);

Charge,Q= 233,841.75 coulumb.

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