The question is incomplete, here is the complete question:
Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.
<u>Answer:</u> The mole fraction of KCl in the solution is 0.044
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of water = 225 g
Molar mass of water = 18 g/mol
Putting values in equation 1, we get:

Given mass of KCl = 43 g
Molar mass of KCl = 74.55 g/mol
Putting values in equation 1, we get:

Mole fraction of a substance is given by:

Moles of KCl = 0.577 moles
Total moles = [0.577 + 12.5] = 13.077 moles
Putting values in above equation, we get:

Hence, the mole fraction of KCl in the solution is 0.044
It is primarily used as a way to supply energy to other cells
Answer:
Hi
The high dipole moment of water and its ease in forming hydrogen bonds make it an excellent analysis. A molecule is soluble in water if it can interact with its molecules through hydrogen bonds or ion-dipole interactions.
With anions that have oxygen they can form hydrogen bonds, since oxygen acts as their acceptor. The attraction of the anion on the water dipole must be taken into account. The same goes for Cl-F, which have solitary electron pairs and can act as hydrogen bridge acceptors. On the other hand, cations such as Na+, K+, Ca++ or Mg++ are surrounded by water molecules to which they are joined by dipole ion interactions while oxygen atoms are oriented towards the catión.
Explanation:
There are 11 electrons in Sodium(Na)
The first shell can hold 2 electrons
The second shell can hold 8 electrons
The third shell can also hold 8 electrons but there is only 1 left
so the answer is 2, 8, 1