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Mazyrski [523]
3 years ago
6

Are BF3 and NF3 symmetric or asymmetric molecules? explain your reasoning

Chemistry
1 answer:
e-lub [12.9K]3 years ago
3 0
The shape of the molecule depends on how many electrons and bonds you have in the outer shell of the central atom. 
For NH3, N is the central atom. It has 3 covalent bonds and a lone pair. Thus the repulsion of the lone pair electrons and the bond electrons will force them to arrange at the corners of a tetrahedral. The molecule will look as a trigonal pyramid (since the lone pair is not "visible" in the structure. 

<span>For BH3, B is the central atom and has no lone pair apart from the three bonds. So the repulsion of the bond electrons will force them to be in a planar trigonal arrangement.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
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When 240 mg of a certain molecular compound X are dissolved in 35.0 g of dibenzyl ether ((C6H5CH2)2O), the freezing point of the
DedPeter [7]

Answer: MM = 16.55 g/mol

Explanation: <u>Freezing</u> <u>point</u> <u>depression</u> is a phenomena that explains why adding a solute to a solvent decreases the solvent freezing point: when a substance begins to freeze, its molecules slows down and rearrange itself forming a solid. If a solute is added, the molecules from the solvent interfere in the formation of the solid. To guarantee the transformation, the solution has to cooled down even more.

Freezing point and molality concentration is related by

\Delta T=T_{f}_{(solvent)}-T_{f}_{(solution)}=K_{f}.m

where

ΔT is freezing point depression

T_{f}_{(solvent)} and T_{f}_{(solution)} are freezing point of solvent and solution, respectively

K_{f} is freezing point depression constant

m is molality concentration

<u />

Dibenzyl ether is the solvent and has the following properties: K_{f}= 6.27 and T_{f} = 3.6°C.

Molality concentration is

m=\frac{T_{(solvent)}-T_{(solution)}}{K_{f}}

m=\frac{3.6-1}{6.27}

m = 0.415

<u>Molality</u> <u>concentration</u> is moles (n) of solute dissolved in a mass, in kilogram, of solvent.

m=\frac{moles}{mass(kg)}

n = m(mass of solvent in kg)

n = 0.415(0.035)

n = 0.0145

<u>Molar</u> <u>mass</u> (M) is the weight of one sample mole and can be calculated as

n=\frac{m}{M}

M = \frac{m}{n}

m in grams

Molar mass of compound X is

M=\frac{0.24}{0.0145}

M = 16.55

<u>Molar mass of molecular</u><u> compound X is 16.55g/mol</u>

3 0
3 years ago
6) Using the rules for significant figures, the sum of 0.027 gram
densk [106]

Answer:

it would be C

Explanation:

8 0
3 years ago
Read 2 more answers
Assume that your electrical power company gets its energy from a hydroelectric dam. Outline all of the energy changes that occur
Rina8888 [55]

Answer:

See explanation.

Explanation:

This isn't chemistry. Its physics. Kinetic energy (water) to electric energy (dam) as the hydroelectric dam works. Then, as the current travels from the plant to your crib, electric energy to heat energy (wire resistance). Then when you are using the dryer electric energy to heat energy (hot air) and sound energy (air particles vibrate due to the heat energy).

5 0
2 years ago
A certain reaction has an enthalpy of Δ=44 kJ and an activation energy of a=61 kJ. What is the activation energy of the reverse
avanturin [10]

Answer:

E = 17 kJ

Explanation:

The enthalpy of the reaction is:

\Delta H = E_{p} - E_{r}  

<u>Where</u>:

Ep: is the energy of the products

Er: is the energy of the reactants

Similarly, the enthalpy of the reaction is related to the activation energy forward (E_{F}) and to the activation energy reverse (E_{R}) as follows:

\Delta H = E_{F} - E_{R}  

Having that ΔH = 44 kJ and E_{F} = 61 kJ, the activation energy of the reverse reaction is:

E_{R} = E_{F} - \Delta H = 61 kJ - 44 kJ = 17 kJ  

Therefore, the activation energy of the reverse reaction is 17 kJ.

I hope it helps you!

3 0
3 years ago
Please hurry this is due tomorrow morning
Llana [10]
Answer: G Atom 1 and Atom 4.. hope this helps and good luck!
3 0
3 years ago
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