Answer:
9302 moles of CO contain 5.60×10²⁷ molecules
Explanation:
We solve this with Avogadro's number.
NA = 6.02×10²³
This number states the how many particles are in 1 mol of anything.
1 mol of atoms contains 6.02×10²³ atoms
1 mol of molecules contains 6.02×10²³ molecules.
We apply a rule of three:
6.02×10²³ molecules are contained in 1 mol of CO
Then, 5.60×10²⁷ molecules may be contained in (5.60×10²⁷ . 1) / 6.02×10²³
= 9302 moles
(a) benzene (C6H6) - <span>nonpolar molecules . Only dispersion forces are present.
</span>
(b) CH3Cl - <span>Chloroform ; polar molecules. Both dispersion and dipole-dipole forces are
present.
</span>
(c) PF3 - <span>Phosphorus triflouride ; has polar bonds but has nonpolar molecule due to its symmetrical structure. Only dispersion forces are present.
</span><span>
(d) NaCl - </span><span>Sodium chloride ; ionic compound. Both ion-ion and dispersion forces are present.</span><span>
(e) CS2 - </span><span>Carbon disulfide ; nonpolar molecules. Only dispersion forces are present.</span>
Answer:
I predict the reaction between __Fe___ and __CuSO___ will yield a _____single replacement_____ reaction/s.
I predict the reaction between ___ Pb(NO3)2__ and __ Kl___ will yield a _____ double replacement_____ reaction/s.
I predict the reaction between ___Mg__ and __HCI___ will yield a ____Single replacement______ reaction/s.
I predict the reaction between __ electrolysis___ and _____ will yield a ____ decomposition______ reaction/s.
I predict the reaction between __ Mg___ and __ O2___ will yield a ____ synthesis and inorganic combustion______ reaction/s.
Explanation:
<span>The correct answer is ideal gas law.
when the ideal gas law formula is:
PV = nRT ,
when P is the pressure.
V is the volume.
and R is the ideal gas constant.
T is the temperature.
and n is the number of moles.
So, this is the law which relates pressure, temperature, volume and number of moles . and this law state that 1 mole of an ideal gas will occupy a volume V = 22.4 L</span>
Answer:
limestone+heat=marble
sandstone+heat=metaquartzite
shale+heat=quartzite
