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hodyreva [135]
3 years ago
15

Which of the following is a possible application for discoveries made during ocean exploration?

Chemistry
1 answer:
bogdanovich [222]3 years ago
4 0
The answer is all of the above.     I got it correct

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Which term refers to the energy emitted when an electron moves from a higher energy level to a lower one?
Stells [14]
When it switches to a lower orbital, the atom emits energy in the form of photons.
4 0
4 years ago
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If 30cm³ of 0.45 mol dm3 HCl reacted with NaOH, how many moles of HCl reacted?​
77julia77 [94]

Moles HCl reacted : 0.0135

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

The volume of HCl 30 cm³=3.10⁻² dm³

Molarity of HCl = 0.45 mol/dm³

so moles HCl reacted :

\tt n=3.10^{-2}\times 0.45=0.0135

3 0
3 years ago
What is the temperature of 0. 750 mol of a gas stored in a 6,850 ml cylinder at 2. 21 atm?.
victus00 [196]

-246 K-

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3 0
2 years ago
Is Neon a metal, nonmetal, or a metalliod
natulia [17]
Neon is a nonmetal.....

5 0
3 years ago
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Using a spectrophotometer, and a cuvette with a path length of 1 cm you measure the absorbance (A275) of Guanosine to be 0.70. C
Anton [14]

Answer : The concentration of guanosine in your sample is, 8.33\times 10^{-5}M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution  = 0.70

C = concentration of solution = ?

l = path length = 1.00 cm

\epsilon = molar absorptivity coefficient guanosine  = 8400M^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

0.70=8400M^{-1}cm^{-1}\times C\times 1.00cm

C=8.33\times 10^{-5}M

Thus, the concentration of guanosine in your sample is, 8.33\times 10^{-5}M

5 0
3 years ago
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