Step-by-step explanation:
-3. 2
-2. 1
-7. 6
i did my best.
The polynomial function of the least degree with integral coefficient that has the given zeros is <span>y = (x+2)(x-2)(x-4)(x-6). I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications about the said problem.</span>
Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
First integrate the entire thing by letting multiplying by 1/2 the entire expression raised to exponent 1/2 - 1. That is,
0.5(1 + x³)^-0.5
Then, multiplying this by the derivative of those inside the parentheses. The final answer would be,
(0.5)((1 + x³)^-0.5)(3x²)
so the line is dog so we know the full line is 60 units long. The 2 parts (do and og) add up to the full length so we can make the equation:
(4x-3)+(2x+21)=60
6x+18=60
6x=42
x=7
if you need to fine do or og, just plug in x to its equation
