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Ira Lisetskai [31]
3 years ago
11

The magnetic moment m⃗ of a current loop is defined as the vector whose magnitude equals the area of the loop times the magnitud

e of the current flowing in it (m=IA), and whose direction is perpendicular to the plane in which the current flows. Find the magnitude, F, of the force on the loop from Part A in terms of the magnitude of its magnetic moment. Express F in terms of m, I2, a, d, and μ0.
Physics
1 answer:
olga_2 [115]3 years ago
7 0

Answer:

Explanatiocn:

F= I1*a*uo*I2*((1/2pi(d-0.5a)-(1/2pi(d+0.5a)) since m=I/A, then I= m/A F = (m/A)*a*uo*I2*((1/2pi(d-0.5a)-(1/2pi(d+0.5a)

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Answer:

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3 years ago
Match each term with its best description.
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Read 2 more answers
Beginning at time t = 0, a student exerts a horizontal force on a box of mass 30 kg, causing it to move at 1.2 m/s toward an ele
Alexandra [31]
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<span>

<span>Thus, the horizontal force exerted must be 58.8 N. 

--------------------------------------


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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