Answer:
0.2 m/s^2
Explanation:
initial speed 14m/s
final speed 20m/s
acceleration:
(20m/s - 14m /s) /30s = (6m/s)/30s = 0.2 m/s^2
Answer:
80 ft/s
Explanation:
Use III equation of motion
V^2 = U^2 + 2g h
Here, U = 0, g = 32 ft/s^2, h = 100 ft
V^2 = 0 + 2 × 32 ×100
V^2 = 6400
V = 80 ft/s
Yes, that's correct. The note "A" (which is used to tune the other strings of the guitar) corresponds to a frequency of 440 Hz.
