Hello!
Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:
← The circumference of the orbit
speed = orbital speed, we will solve for this later
time = period
Therefore:
Where 'r' is the orbital radius of the satellite.
First, let's solve for 'v' assuming a uniform orbit using the equation:
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = mass of the earth (5.98 × 10²⁴ kg)
r = radius of orbit (1.276 × 10⁷ m)
Plug in the givens:
Now, we can solve for the period:
Answer:
Explanation:
Given
-- radius of hydrogen atom
<em>See attachment</em>
Required
Determine the radius of magnesium atom (R)
From the attachment, the ratio of a hydrogen atom to a magnesium atom is:
Simplify
Represent the radius as ratio:
Substitute
Equate both ratios
Express as fraction
Cross Multiply
Hence, the radius of the magnesium atom is:
Answer:
Explanation:
m = Order = 1
D = Distance between screen and slit = 3.09 m
d = Slit distance = 1.01 mm
= Wavelength = 639 nm
Distance from the first bright fringe from the central bright fringe is given by
Distance from the first bright fringe from the central bright fringe is
Distance from the second dark fringe from the central bright fringe is given by
Distance from the second dark fringe from the central bright fringe is .