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3 years ago

What is the force weight of a jaguar who jumps 3 meters to a tree branch with 2670 J of work?

Physics

1 answer:

fgiga [73]3 years ago

7 0

Answer:

$we \: know \: energy \: = \: force \: \times distance \\ e = f \times d \\ so \: f \: = \frac{e}{d} \\ so \: th \: force \: here \: = (\frac{2670}{3}) newton \\ = 890newton$

Hope it helps

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Unpolarized light is incident upon two ideal polarizing filters that do not have their transmission axes aligned. If 14% of the

vladimir1956 [14]

Answer:

A) 58 degree

Explanation:

When unpolarized light passing through first polarizer then the intensity of light becomes half as it will get polarized

So let say the intensity of unpolarized light is "Io" then after passing through first polarizer the intensity will become half

Now when this polarized light passing through another polarizer then the intensity of light is given by Malus law

As per Malus law if the angle between two polarizer axis is inclined at some angle

then it is given as

$I = I_0 cos^2\theta$

$0.14I_0 = 0.5I_0cos^2\theta$

$0.28 = cos^2\theta$

$\theta = 58 degree$

6 0

4 years ago

An old clock has a spring that must be wound to make the clock hands move. Which statement describes the energy of the spring an

kondaur [170]

Answer:

Explanation:

When the spring is wound, then it gathers potential energy in the form of tension energy. As it slowly unwinds, the potential energy is converted to kinetic energy of the hands' movements of the clock. This energy is channeled through the use of cogs/gears in the clock.

7 0

3 years ago

Read 2 more answers

Two geological field teams are working in a remote area. A global positioning system (GPS) tracker at their base camp shows the

Masja [62]

Answer:

distance of 2nd team from 1st team will be: 58.2

Direction of 2nd team from 1st team will be: 14.90 deg North of east

Explanation:

ASSUME Vector is R and makes angle A with +x-axis,

therefore component of vector R is

$R_x = Rcos A$

$R_y = Rsin A$

From above relation

Assuming base camp as the origin, location of 1st team is

$R_1 = 37 km$ away at 21 deg North of west (North of west is in 2nd quadrant, So x is -ve and y is positive)

$R_{1x} = -R_1*cos A_1 = -37*cos 21 deg = -34.54 km$

$R_{1y} = R_1*sin A_1 = 37*sin 21 deg = 13.25 km$

location of 2nd team is at

$R_2 = 32 km$ , at 38 deg East of North = 32 km, at 58 deg North of east (North of east is in 1st quadrant, So x and y both are +ve)

$R_{2x} = R_2*cos A_2 = 32*cos 58 deg = 16.95 km$

$R_{2y} = R_2*sin A_2 = 32*sin 58 deg = 27.13 km$

Now position of 2nd team with respect to 1st team will be given by:

$R_3 = R_2 - R_1$

$R_3 = (R_{2x} - R_{1x}) i + (R_{2y} - R_{1y}) j$

Using above values:

$R_3 = (16.95 - (-34.54)) i + (27.13 - 13.42) j$

$R_3 = 51.49 i + 13.71 j$

distance of 2nd team from 1st team will be:

$\left | R_3 \right | = \sqrt (51.49^2 +13.71^2)$

$\left | R_3 \right | = 53.28 km = 58.2 km$

Direction of 2nd team from 1st team will be:

$Direction = tan^{-1} \frac{R_{3y}}{R_{3x}} = tan^{-1}[ \frac{13.71}{51.49}]$

Direction = 14.90 deg North of east

6 0

3 years ago

State the difference between sensible heat and latent heat

Anna11 [10]

<u>Latent hea</u>t is related to changes in phase between liquids ,gases and solids.

<u>Sensible heat</u> is related to changes in temperature of a gas or object with no change in phase.

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3 years ago

What are the body parts to this figure? Any of the body parts. (Please)

vlabodo [156]

1 - Skull
2 - Mandible
3 - Scapula
4 - Sternum
5 - Ulna
6 - Radius
7 - Pelvis
8 - Femur
9 - Patella
10 - Tibia
11 - Fibula
12 - Metatarsals
13 - Clavicle
14 - Ribs (rib cage)
15 - Humerus
16 - Spinal column
17 - Carpals
18 - Metacarpals
19 - Phalanges
20 - Tarsals
21 - Phalanges

3 0

3 years ago