The number of customers I would have expected to win the prize is 6.
<h3>How many more customers would I have expected to win the prize?</h3>
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
Based on the probability, the number of customers I would have expected to win: 0.18 x 300 = 36
How many more people I would have expected to win : 36 - 30 = 6
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<span>1--- f(x) = 4 - 3 sin x = 2
-3 sin x = -2
sin x = 2/3
x ≈ 0.7297276562... ≈ 0.73
2--- -1 ≤ sin x ≤ 1
-3 ≤ 3 sin x ≤ 3
3 ≥ -3 sin x ≥ -3
7 ≥ 4 - 3 sin x ≥ 1
If k < 1 or k > 7, there is no solution.
3--- A = 3π/2
4--- g(x) = 4 - 3 sin x = y
4 - 3 sin y = x
4 - x = 3 sin y
(4 - x)/3 = sin y
sin^-1 (4 - x)/3 = y= g^-1
g^-1 (3) = sin^-1 (4 - 3)/4 = sin^-1 1/4 = 2.8017557... ≈ 2.802
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I think it may be 5+3 and carry the one up top to get the sum of 56.
Answer:
Step-by-step explanation:
(10 - 8)/(-21 + 9)= 12/-12= -1
y - 8 = -1(x + 9)
y - 8 = -x - 9
y = -x - 1
(X+1)(x-6) I think is what you’re asking for?
