The optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
<h3><u>
Solution:</u></h3>
Given that,
<h3><u>The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by:</u></h3>
![d = 1.9[(5.5 \times 10^{-4})l]^{\frac{1}{2}}](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29l%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
where l is the length (in millimeters) of the camera box
<h3><u>Find the optimum pinhole diameter for a camera box with a length of 10 centimeters</u></h3>
l = 10 cm
We know that,
10 cm = 100 mm
<em><u>Therefore, plug in l = 100 in given formula</u></em>
![d = 1.9[(5.5 \times 10^{-4}) \times 100]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-4} \times 10^2]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-2}]^{\frac{1}{2}}\\\\d = 1.9 \times 5.5^{\frac{1}{2} \times 10^{-1}}\\\\d = 0.19 \times 2.345207\\\\d = 0.4455 \approx 0.446](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29%20%5Ctimes%20100%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctimes%2010%5E2%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-2%7D%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%20%5Ctimes%205.5%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2010%5E%7B-1%7D%7D%5C%5C%5C%5Cd%20%3D%200.19%20%5Ctimes%202.345207%5C%5C%5C%5Cd%20%3D%200.4455%20%5Capprox%200.446)
Thus the optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
Answer:
The equivalent expression for 
is 
Step-by-step explanation:
The distance in feet that Karina swims in a race is represented by 4d - 4, where is d is the distance for each lap.
To get equivalent expression we factor the expression 4d-4
Greatest common factor is 4
Factor out 4 from the expression 4d-4
when we factor out 4, we divide each term by 4
The equivalent expression for is
0.5 L/s = ml/h would be clearer if written as 0.5 L/sec = ml/hr.
Start with 0.5 L/sec:
0.5 L/sec 1000 ml 3600 sec
--------------- * ------------- * ---------------- = 1,000,000 ml/hr
1 1 L 1 hr
Answer:
AB = JK = 49
Step-by-step explanation:
Since ABC = JKL
We know the length of AB has to equal the length of JK.
AB = JK
14x+7 = 5x+34
Subtract 5x from each side.
14x-5x +7 = 5x-5x+34
9x+7 = 34
Subtract 7 from each side
9x+7-7 = 34 -7
9x = 27
Divide each side by 9.
9x/9 = 27/9
x =3
AB = 14x+7
Substitute x=3
14(3) +7
42+7
AB = 49
