Answer:
length = 8
width = 4
Step-by-step explanation:
Area = length x breadth
Let x represent the width
length = x + 4
32 = x × (x + 4)
32 = x² + 4x
x² + 4x - 32 = 0
solving using quadratic equation =
(x² - 4x) -32 + 8x
x = 4 or -8
since width cannot be a negative number, we would use 4
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
Her postcard is 5/8 inches over the height limit
Answer:
all of the triangles are right triangles
Answer:
yes
Step-by-step explanation:
