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Phoenix [80]
3 years ago
14

A college basketball court is 94 feet long and 50 feet wide. What is the diagonal length of the court?

Mathematics
1 answer:
g100num [7]3 years ago
4 0
Drawing a diagonal will create two right triangles. So you can use a^2+ b2 =c^2
So approximately 106.47 feet or the square root of 11336
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Which expression is represented by the phrase "9 less than 5 times a number"?
sukhopar [10]
5x - 9.

Five times a number indicates multiplication and less than indicates subtraction. A number would be a variable since it isn’t specified.
6 0
2 years ago
The cost of a pizza is $8.50 plus $1.35 per topping. How many toppings are on a pizza that costs $13.90?
VMariaS [17]

Answer:  

8.50 + 1.35n = 13.90

Step-by-step explanation:

So basically you have to add the cost of pizza and the per toppings correct me if i'm wrong Also Have a good Wonderful day!

And that's 4 toppings

3 0
3 years ago
Read 2 more answers
BRAINLY FOR CORRECT ANSWER! YOU MUST GIVE ME AN ANSWER NOT AN EQUATION.
Nadusha1986 [10]

The answer is 310.93, rounded to the nearest hundredth. Hope this helps!

5 0
2 years ago
In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

6 0
3 years ago
Write the equation of the line that passes through (-1, 3) and is parallel to the line y = -x + 1.
ra1l [238]

Answer:

Step-by-step explanation:

y = -x + 1......same as y = -1x + 1.....in y = mx + b form, ur slope is in the m position....so the slope of this line is -1.

a parallel line will have the same slope.

(-1,3)...x = -1 and y = 3

slope(m) = -1

y = mx + b.....we have x,y, and m....now we need to find y int (b)

3 = -1(-1) + b

3 = 1 + b

3 - 1 = b

2 = b

so ur parallel equation is : y = -1x + 2...or just y = -x + 2

7 0
2 years ago
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