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Phoenix [80]
3 years ago
14

A college basketball court is 94 feet long and 50 feet wide. What is the diagonal length of the court?

Mathematics
1 answer:
g100num [7]3 years ago
4 0
Drawing a diagonal will create two right triangles. So you can use a^2+ b2 =c^2
So approximately 106.47 feet or the square root of 11336
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What are the awnsers<br><br> SHOW WORK!!<br> Please
rusak2 [61]

Answer:

Step-by-step explanation:
The rules For fractions: Multiple Denominator to Denominator and Numerator to numerator!

Ok: For number 1

3/5*1/1= 3/5

Number 2

3/4*9/4=27/16= 1 11/16

Number 3

14/21=2/3*33/7=66/21= 3 3/21= 3 1/7

Number 4

6/18*9/42= 1/3*3/14= 3/42= 1/14

Number 5

22/15*45/4= 33/2=16 1/2

Number 6

3/28* 35/6= 105/168= 5/8

Number 7

2/7*35/12=60/84=5/6

Number 8

16/15*21/24=16/15* 7/8=112/120=14/15

Hope It helps!!!!

7 0
1 year ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
Fran has 7 sheets of paper for a colouring project. If she only uses 1/3 of a sheet of paper per drawing how many drawings can s
Sav [38]
So we can make an equation for this, being 7=1/3x, as that effectively says she can make 3 drawings per page.

Knowing this, we can multiply it by 3 to get x=21 (since if she can draw 3 drawings per page, we can imagine that if each drawing took a page she would need 3 times the pieces of paper), therefore she can make 21 drawings.
8 0
3 years ago
A rectangular swimming pool has a length of 50 m, a width of 25 m, and a depth of 1.75 meters. What is the volume of water neede
Ahat [919]

Answer:

2187.5 cubic meters of water

Step-by-step explanation:

Volume of rectangle = L * W * D

V = 50 * 25 * 1.75

V = 2187.5

5 0
3 years ago
Read 2 more answers
The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
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