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Sunny_sXe [5.5K]

3 years ago

7

CALCULATOR COLOR THEME 0 ZOOM 2. Danielle wants to translate triangle XYZ so that vertex Yis mov (-4,2) to (0,-3). Which of the

following mappings can be used to coordinates of Xand Z?

1 answer:

pogonyaev3 years ago

6 0

Answer:The answer is (x,y)->(+4,y-5)

Step-by-step explanation:

since -4 to 0 is + 4 and 2 to -3 is -5

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How to round to the nearest degree

Anika [276]

Answer:

to the nearest whole degree means that you look at the first decimal place. if it is less than 5, you keep the whole number and eliminate the decimal. if otherwise, the decimal is ≥5, you round up the whole number and eliminate the decimal.

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4 years ago

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I need help on this one ?

soldier1979 [14.2K]

Answer:

1.5^2 = 2.25

(it looks like 1.5 but if it's 15 then it would be 225)

Step-by-step explanation:

1.5^2 means (1.5*1.5) you multiply the number by itself by how many it says to do. So if it were 1.5^52 you would multiply 1.5 by 1.5, 52 times.

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4 years ago

What's 60 twenty-fives minus 1 twenty-five<br><br> written in number from

Lilit [14]

Answer:

(60 x 25) - 25 = 1475

Step-by-step explanation:

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3 years ago

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Anybody help me to solve this question.

Mumz [18]

Answer:

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP$

Step-by-step explanation:

Given that $(b-c)^2, (c-a)^2 , (a-b)^2$ are in AP

To prove: $\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}$ are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

$2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab$

Now

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc$

Which is the result of AP

.

Hence proved

6 0

3 years ago

Suppose that 1 month before the election a random sample of 500 registered voters are surveyed. From this sample 270 indicate th

Aleonysh [2.5K]

Answer:

[ 0.4964, 0.5836 ]

Step-by-step explanation:

Data provided in the question:

Total sample size = 500

person voting for smith = 270

thus,

P( person voting for smith ), p = $\frac{270}{500}$ = 0.54

Confidence level = 95%

now,

standard error, SE = $\sqrt{\frac{p(1-p)}{n}$

or

SE = $\sqrt{\frac{0.54(1-0.54)}{500}$

or

SE = 0.0223

now,

Confidence interval = p ± ( z × SE )

here,

z value for 95% confidence interval is 1.96

Confidence interval = [ 0.54 - ( 1.96 × 0.0223 ), 0.54 + ( 1.96 × 0.0223 ) ]

= [ 0.54 - 0.0436 , 0.54 + 0.0436 ]

= [ 0.4964, 0.5836 ]

8 0

3 years ago