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kobusy [5.1K]
3 years ago
12

3. Determine the Zeff value of Uranium, also indicate (based on your answer with mathematical calculations) which electron will

be closest to the nucleus of this element: 5s, 5p, 5f or 5d.
Chemistry
1 answer:
Ilya [14]3 years ago
3 0

Explanation:

Electronic configuration of uranium is given below -

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p⁶4f¹⁴5d¹⁰6s²6p⁶5f³6d¹7s2²

Effective nuclear charge (Z eff) = Atomic number (Z) - Shielding constant (S)

<u> Value of Shielding constant (S) can be calculated by using slater's rule : </u>

S = 1 (0.35) + 9 (0.85) + 81 (1.00)

S = 0.35 + 7.65 + 81.00

S = 89

So,

Zeff = Z - S

Zeff = 92 - 89

<u> Zeff = 3 </u>

Hence, Effective nuclear charge (Zeff) of uranium = <u>3 </u>

5s electron is closest to the nucleus.

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Answer:

The answer is "\bold{HClO_3 > HClO_2 >HClO > HBrO}"

Explanation:

We arrange oxoacids to decrease the intensity of acids in this question. Or we may conclude all this from strongest to weakest acids they order oxoacids, that's why above given order is correct.

5 0
3 years ago
A 500.0 g block of dry ice (solid CO2, molar mass = 44.0 g) vaporizes at room temperature. Calculate the volume of gas produced
Damm [24]

Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

<h3>Definition of ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Ideal gas law</h3>

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

<h3>Volume of gas</h3>

In this case, you know:

  • P= 1.50 atm
  • V= ?
  • n= 500 g×\frac{1 mole}{44 g}= 11.36 moles, being 44 \frac{g}{mole} the molar mass of CO₂
  • R= 0.082 \frac{atmL}{molK}
  • T= 25 C= 298 K (being 0 C=273 K)

Replacing in the ideal gas law:

1.50 atm×V = 11.36 moles×0.082\frac{atmL}{molK} × 298 K

Solving:

V= (11.36 moles×0.082\frac{atmL}{molK} × 298 K) ÷ 1.50 atm

<u><em>V= 184.899 L</em></u>

Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

Learn more about the ideal gas law:

<u>brainly.com/question/4147359?referrer=searchResults</u>

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