Answer:
Phosphatidylcholine also known as lecithin
Explanation:
The most common phospholipids in order of abundance are
1). phosphatidylcholine, lecithin
2). phosphatidylethanolamine, cephalins 3).phosphatidylinositol, and 4).phosphatidylserine.
They have the common characteristics of esterified fatty acids to the 1 and 2 positions of the glycerol structure with the esterified phosphate group to the 3 position
In order to calculate the molar mass of the protein, we may manipulate the ideal gas equation:
PV = nRT, where n is the number of moles. We also know that:
n = m / Mr, where m is mass and Mr is molecular weight
Thus,
Mr = (mRT)/(PV)
Here, the mass is in grams, the temperature is in Kelvin, the pressure is in atm and the volume is in liters, so the molar gas constant is 0.082057.
Mr = (3.6 * 0.082057 * (27 + 273)) / (0.0203 * 0.2)
Mr = 21,828 g/mol
Thus, the Mr of the protein is 2.18 x 10⁴ g/mol
Answer: The value of
is 0.0012 M and
is
.
Explanation:
pH is the negative logarithm of concentration of hydrogen ion.
It is given that pH is 2.89. So, the value of concentration of hydrogen ions is calculated as follows.
![pH = - log [H^{+}]\\2.89 = - log [H^{+}]\\conc. H^{+} = 0.0012 M](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5C2.89%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5Cconc.%20H%5E%7B%2B%7D%20%3D%200.0012%20M)
The relation between pH and pOH value is as follows.
pH + pOH = 14
0.0012 + pOH = 14
pOH = 14 - 0.0012 = 13.99
Now, pOH is the negative logarithm of concentration of hydroxide ions.
Hence,
is calculated as follows.
![pOH = - log [OH^{-}]\\13.99 = - log [OH^{-}]\\conc. OH^{-} = 1.02 \times 10^{-14} M](https://tex.z-dn.net/?f=pOH%20%3D%20-%20log%20%5BOH%5E%7B-%7D%5D%5C%5C13.99%20%3D%20-%20log%20%5BOH%5E%7B-%7D%5D%5C%5Cconc.%20OH%5E%7B-%7D%20%3D%201.02%20%5Ctimes%2010%5E%7B-14%7D%20M)
Thus, we can conclude that the value of
is 0.0012 M and
is
.
<u>Answer:</u> The pressure of NO and
in the mixture is 0.58 atm and 0.024 atm respectively.
<u>Explanation:</u>
We are given:
Equilibrium partial pressure of
= 0.29 atm
For the given chemical equation:

Initial: a
At eqllm: a-2x 2x x
Calculating for the value of 'x'

Equilibrium partial pressure of NO = 2x = 2(0.29) = 0.58 atm
Equilibrium partial pressure of
= a - 2x = a - 2(0.29) = a - 0.58
The expression of
for above equation follows:

We are given:

Putting values in above expression, we get:

Neglecting the value of a = 0.555 because it cannot be less than the equilibrium concentration.
So, 
Equilibrium partial pressure of
= (a - 0.58) = (0.604 - 0.58) = 0.024 atm
Hence, the pressure of NO and
in the mixture is 0.58 atm and 0.024 atm respectively.
after a volcanic eruption is the answer
Mudflows of volcanic eruptions are the most dangerous, and are called lahars