Answer:
[KIO₃] = 0.548 M
Explanation:
Molarity is a sort of concentration which involves moles of solute in 1L of solution.
Volume of solution 5L
Mass of solution: 587 g
Let's convert the mass to moles (mass / molar mass)
587 g / 214 g/mol = 2.74 moles
Molarity is mol/L → 2.74 mol / 5L = 0.548 M
Sulfur dioxide formula is : SO2
Hyrdrogen monobromide is : HBr
Hope this helped :)
Answer:
A. 15
Explanation:
From the equation we see that 6 water particles are used to make 1 particle of the hexose.
That means, that to make 1 mole of the hexose, we need 6 moles of water (as a mole is an unit of count of particles).
To make 2.5moles of the hexose, we need 2.5*6 moles of water, so 15 moles of water.
The balanced NET ionic equation for the reaction is CrBr₃(aq) + Na₃PO₄(aq) ==> CrPO₄(s) + 3NaBr(aq)
<h3>What is a balanced Ionic equation ?</h3>
In a balanced ionic equation, the number and type of atoms are the same on both sides of the reaction arrow.
Additionally, the net charge is the same on both sides of the equation.
Separate into the complete ionic equation.
It should be obvious that the aquous solutions ionize and the solid is shows as the molecule since it doesn't dissolve.
Cr³⁺(aq) + 3Br⁻(aq) + 3K⁺(aq) + PO₄³⁻(aq) ==> CrPO₄(s) + 3K⁺(aq) + 3Br⁻(aq)
Now look and cancel those ions common to both sides. What is left is the net ionic equation.
Cr³⁺(aq) + PO₄³⁻aq) ==> CrPO₄(s)
Learn more about balanced Ionic equation here ;
brainly.com/question/16463650
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Answer:
The yield percent is 77.68%
Explanation:
1 mole of yields 2 moles of Fe.
So, 11.2 moles of Iron(III) oxide must yield 22.4 moles of Fe theoretically. This is according to the balanced equation.
Theoretical Yield = 22.4 moles of Fe
Experimental Yield = 17.4 moles of Fe
Therefore, the yield percent is 77.68%