Answer:
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Answer:
250cm³ de disolución se deben preparar
Explanation:
El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.
Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³
Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:
50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =
<h3>250cm³ de disolución se deben preparar</h3>
The combustion of ammonia in presence of excess oxygen yields NO2 and H2O.
The molar mass of ammonia is 17.02 g/mol
Therefore, moles of ammonia in 43.9 g
= 43.9 /17.02
= 2.579 moles
From the equation the mole ratio of ammonia to nitrogen iv oxide is 4:4
The molar mass of NO2 is 46 g/mol
The number of moles of NO2 is the same as that of ammonia since they have equal ratio,
= 2.579 moles
Therefore, mass of NO2
= 2.579 moles ×46
= 118.634 g
≈ 119 g
Answer:
Explanation:
Fe₂O₃(s) + 3H₂(g) = 2Fe (s) + 3H₂O - 98.8 kJ .
one mole of ferric oxide reacts with 3 mole of hydrogen to give 2 mole of iron and 3 mole of water . 98.8 kJ of heat is absorbed .
The SI I would use is inches, because inches is a reasonable length for a computer. However, Centimeter is too short and yards is too long. That is why inches is great for measuring a computer with.
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