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blsea [12.9K]
3 years ago
11

Evaluate 5(x + y) for x = 3 and y = 9. +

Mathematics
1 answer:
Elza [17]3 years ago
5 0

Answer:

60

Work:

3+9=12

12•5=60

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-7x^2+10=185 how to solve
bonufazy [111]

Answer:

-7x²=185-10

-7x²=175

x²=-25

x=±√-25

6 0
3 years ago
What is the answer to the problem-4n=-68
klasskru [66]

Answer: n = 17

Step-by-step explanation: n= -68/-4= 17

4 0
3 years ago
Read 2 more answers
the volume of cube A is 216 cubic inches. the length of each edge in cube B is 2 inches longer than the length of each edge in c
Aleonysh [2.5K]
If the side lengths of B are 2x as long as the side lengths of A then the volume of B should be the volume of A^2
216^2=46,656
46,656-216=46,440

This can be more easily displayed with smaller numbers

If cube X were 2*2*2 then the volume would be 8
If cube Y were 4*4*4 then the volume would be 64
8(volume of cube X)^2=64(volume of cube Y)
7 0
3 years ago
Every valid argument with true premises has a true conclusion. Rewrite the above statement in the form V[x] x, if [y] then [z] (
just olya [345]

Answer:

Let y(x)="x is valid and x has true premises" and z(x)="x has a true conclusion".

Step-by-step explanation:

The universe U is the collection of all arguments so that x∈U. The statement uses the universal quantifier ∀ represented by the word "Every". The words "valid", "with true premises" and "has a true conclusions" are properties of an argument x.

We can interptet the statement as: "For all x, (x is valid and x has true premises)→(x has a true conclusion)". Symbolically, (∀x)(y(x)→z(x)). The implication → can be read as "if y(x) then z(x)".

4 0
3 years ago
① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method
hram777 [196]

Answer:

<h2>S = 9/20</h2><h2>J = 113/50</h2>

Step-by-step explanation:

5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\  S = 9/20\\

Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50

4 0
3 years ago
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