Answer:

Step-by-step explanation:
Given lines,
y = 2x - 5,
y = -x + 1
Subtracting these two equations,
0 = 3x - 6


By first equation,

Thus, point of intersecting would be (2, -1).
Now, the equation of a line is y = mx + c,
Where,
m = slope of the line,
So, the slope of the line
is 1/2.
∵ two parallel lines have same slope.
Hence,
Equation of the parallel line passes through (2, -1),



Answer:
The Answer Is:
B. The Slope is 0
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- Innverted
If n is rational, it means that

Therefore when we do n² we can write it as

Remember that the product of two integer numbers is also an integer, therefore we can guarantee that

Then we can confirm that n² is the quotient of two integers and the denominator is not zero, therefore, n² is always rational, it cannot be an irrational number
Answer:
150 units^2
Step-by-step explanation:
A=6a2=6·52=150
The new y-intercept would be A)-1 because of the 4-5 = -1