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3 years ago

Twenty liters of NO gas react with excess oxygen. How many liters of NO2 gas are produced if the NO gas reacts completely?

Chemistry

1 answer:

Umnica [9.8K]3 years ago

8 0

Answer:

2O L

Explanation:

The balanced chemical equation is 2NO+O

→2NO

Thus, 2 moles of NO will produce 2 moles of NO

Also, the volume is directly proportional to the number of moles.

Therefore, 20 L of NO will produce 20×

=20 L of NO

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As a science major, you are assigned to the "Atomic Dorm" at college. The first floor has one suite with one bedroom that has a

lidiya [134]

Explanation:

The first student will be on the lower bunk on the first floor because 1. They want on the lowest available floor and 2. They want to be in a lower bunk if available.

7 students are in the TOP bunks because 1. They want on the lowest available floor and 2. They want to be in a lower bunk if available. Therefore, all the rooms up till the third floor (Remember, third floor has 3 suites), so the first floor is filled - 1 person on the top bunk, 2 floor is filled- 4 persons and the third floor; the first suite is filled - 1 person and the second suite is a little partially filled- 1 person.

Following the criteria 1, 2 and 3, the 21st student occupies the third suite on the third floor because all the floors (1 and 2) are occupied so the third suite on the third floor is still vacant.

From the criteria there are therefore 10 persons at the TOP bunk. All the rooms up till the third floor are filled, so the first floor is filled - 1 person on the top bunk, second floor is filled (2 suites) - 4 persons and the third floor; the first suite and second suite is filled - 4 persons; the thirs suite has 6 persons present so 1 person is at the top bunk.

8 0

4 years ago

An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 5.00g of this compound produced 7.33g of

Olegator [25]

A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:

Organic Compound + Oxygen = CO2 + H2O

To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.

7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C

Therefore, 0.167 mol of C was originally in the sample.

8 0

3 years ago

Read 2 more answers

Your lab partner dissolves 0.8392 g unknown bromide (Br-) sample into 210.08 mL of distilled water. 31.50 mL of the unknown brom

nikitadnepr [17]

Answer:2

Explanation:

4 0

3 years ago

Calculate the concentration of oxalate ion (c2o42–) in a 0.175 m solution of oxalic acid (c2h2o4). [for oxalic acid, ka1 = 6.5 ×

Darina [25.2K]

C2H2O4 C2HO4- + H+

0.175 - x x x + y

C2HO4- c2o42– + H+

x - y y x + y

K2 = (y) (x +y) / (x-y)

As, y << x

So, K2 = (y) (x) / (x)

K2 = y =6.1 × 10^–5

Hence, concentration of (c2o42–) 6.1 × 10^–5 M

7 0

4 years ago

some students believe that teachers are full of hot air. If I inhale 3.5 liters of gas at a temperature of 19 degrees Celsius an

Afina-wow [57]

Answer:

3.97 L

Explanation:

Data obtained from the question include the following:

Initial volume (V1) = 3.5 L

Initial temperature (T1) = 19 °C

Final temperature (T2) = 58 °C

Final volume (V2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be done as shown below:

Temperature (K) = temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 19 °C

Initial temperature (T1) = 19 °C + 273 = 292 K

Final temperature (T2) = 58 °C

Final temperature (T2) = 58 °C + 273 = 331 K

Finally, we shall determine the new volume of the gas by using Charles' law equation as shown below:

Initial volume (V1) = 3.5 L

Initial temperature (T1) = 292 K

Final temperature (T2) = 331 K

Final volume (V2) =..?

V1 /T1 = V2 /T2

3.5 /292 = V2 /331

Cross multiply

292 x V2 = 3.5 x 331

Divide both side by 292

V2 = (3.5 x 331) / 292

V2 = 3.97 L

Therefore, the new volume of the gas is 3.97 L.

5 0

3 years ago