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hram777 [196]
3 years ago
5

Can you answer all of the questions plz

Chemistry
2 answers:
NARA [144]3 years ago
3 0
No..............................
storchak [24]3 years ago
3 0
Bend down dnd. D f. F f fnfn
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The volume of a sample of oxygen is 300.0 mL when the pressure is 1.00 atm and the temperature is 27.0°C. At what temperature is
Zina [86]
2.5 i believe i'll keep you updated i'm still trying to check my answers
7 0
3 years ago
Any mixture that is heterogeneous on a microscopic level is a
Nadya [2.5K]
Solution is the answer.
5 0
3 years ago
What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2
Blizzard [7]

Answer:

Cl⁻ was oxidized.

Explanation:

  • 4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

8 0
3 years ago
At a certain temperature the vapor pressure of pure benzene is measured to be . Suppose a solution is prepared by mixing of benz
Marianna [84]

Answer:

P(C₆H₆) = 0.2961 atm

Explanation:

I found an exercise pretty similar to this, so i'm gonna use the data of this exercise to show you how to do it, and then, replace your data in the procedure so you can have an accurate result:

<em>"At a certain temperature the vapor pressure of pure benzene (C6H6) is measured to be 0.63 atm. Suppose a solution is prepared by mixing 79.2 g of benzene and 115. g of heptane (C7H16) Calculate the partial pressure of benzene vapor above this solution. Round your answer to 2 significant digits. Note for advanced students: you may assume the solution is ideal".</em>

<em />

Now, according to the data, we want partial pressure of benzene, so we need to use Raoul's law which is:

P = Xₐ * P°    (1)

Where:

P: Partial pressure

Xₐ: molar fraction

P°: Vapour pressure

We only have the vapour pressure of benzene in the mixture. We need to determine the molar fraction first. To do this, we need the moles of each compound in the mixture.

To get the moles:   n = m / MM

To get the molar mass of benzene (C₆H₆) and heptane (C₇H₁₆), we need the atomic weights of Carbon and hydrogen, which are 12 g/mol and 1 g/mol:

MM(C₆H₆) = (12*6) + (6*1) = 78 g/mol

MM(C₇H₁₆) = (7*12) + (16*1) = 100 g/mol

Let's determine the moles of each compound:

moles (C₆H₆) = 79.2 / 78 = 1.02 moles

moles (C₇H₁₆) = 115 / 100 = 1.15 moles

moles in solution = 1.02 + 1.15 = 2.17 moles

To get the molar fractions, we use the following expression:

Xₐ = moles(C₆H₆) / moles in solution

Xₐ = 1.02 / 2.17 = 0.47

Finally, the partial pressure is:

P(C₆H₆) = 0.47 * 0.63

<h2>P(C₆H₆) = 0.2961 atm</h2>

Hope this helps

7 0
3 years ago
Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles of O₂ to t
djverab [1.8K]

Answer : The correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Explanation :

The given balanced chemical reaction is,

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

From the balanced chemical reaction, we conclude that

As, 3 moles of O_2 react to give 2 mole of Fe_2O_3

So, 1 mole of O_2 react to give \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2} moles of Fe_2O_3

Thus, the conversion factor needed to convert the number of moles of O_2 to the number of moles of Fe_2O_3 produced is \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Hence, the correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

7 0
3 years ago
Read 2 more answers
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