Explanation:
Transfer of mass A into stagnant film B depends on the availability of driving force.
Whereas driving force is the pressure difference at the surface of A and the bulk.
As, ![N_{A} \propto (P_{A1} - P_{A2})](https://tex.z-dn.net/?f=N_%7BA%7D%20%5Cpropto%20%28P_%7BA1%7D%20-%20P_%7BA2%7D%29)
![N_{A} = K_{G} \times (P_{A1} - P_{A2})](https://tex.z-dn.net/?f=N_%7BA%7D%20%3D%20K_%7BG%7D%20%5Ctimes%20%28P_%7BA1%7D%20-%20P_%7BA2%7D%29)
Therefore, putting the given values into the above formula as follows.
![N_{A} = K_{G} \times (P_{A1} - P_{A2})](https://tex.z-dn.net/?f=N_%7BA%7D%20%3D%20K_%7BG%7D%20%5Ctimes%20%28P_%7BA1%7D%20-%20P_%7BA2%7D%29)
= ![0.88 \times (0.2 atm - 0.05 atm)](https://tex.z-dn.net/?f=0.88%20%5Ctimes%20%280.2%20atm%20-%200.05%20atm%29)
= 0.132 ![mol/h.ft^{2}](https://tex.z-dn.net/?f=mol%2Fh.ft%5E%7B2%7D)
Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 ![mol/h.ft^{2}](https://tex.z-dn.net/?f=mol%2Fh.ft%5E%7B2%7D)
Answer: B. The anion affects the color of the solution more than the intensity of the color.
Explanation:
An ionic bond is gotten when an electron is transferred from a metal atom to a non-metal one. It should be noted that the ionic bonds simply has an anion and a cation.
An anion is formed when a valence election is gained by a non metal while a cation is formed when the metal ion misplaces a valence electron.
The effect of the anion of an ionic compound on the appearance of the solution is that the anion affects the color of the solution more than the intensity of the color.
Answer:
¾ litters of water was consumed
2.24 litters = 1 mole of water
Therefore ¾÷2.24 moles was consumed
0.33 moles
Answer:
14.68 moles of He
Explanation:
To do this, just remember Avogadro's Constant or Avogadro's number. This constant tells us how many units ( in this case atoms) there are in a mole of ANY type of substance.
Avogadro's constant is 6.022140857 × 10²³ units per mole.
Now that we know how many atoms there are in 1 mole, we can use this as our conversion factor.
8.84 x 10²⁴ atoms of He → moles of He
![8.84\times10^{24} atoms of He\times\dfrac{1moleofHe}{6.022140857\times10^{23}atomsofHe}=14.68molesofHe](https://tex.z-dn.net/?f=8.84%5Ctimes10%5E%7B24%7D%20atoms%20of%20He%5Ctimes%5Cdfrac%7B1moleofHe%7D%7B6.022140857%5Ctimes10%5E%7B23%7DatomsofHe%7D%3D14.68molesofHe)
So the answer would be:
14.68 moles of He