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BartSMP [9]
3 years ago
9

I need help on 1 2 and 3...pls help me

Mathematics
2 answers:
dangina [55]3 years ago
7 0
1. 19
2. One person got 15 on both
3. Slightly higher scores on Quiz 1
Naily [24]3 years ago
5 0
1. 19

2. Yes. One student earned 20 on Quiz 1 and Quiz 2, and another got 15 on Quiz 1 and 15 on Quiz 2.

3. The Quiz 1 scores differentiate from the Quiz 2 scores slightly.


I hope that helped! c:
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There is a Saturday performance at a local theater. A theater charges $9 for an adult ticket and $4 for a child ticket. All 1020
Whitepunk [10]
Let x tickets sold be adults, then (1024-x) were of childrens tickets, 9x+(1024-x)4 = 7680. The above equation is for total money solve it you will get x=720 hence, number of adult tickets were 720 and number of child tickets were 300 :)
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3 years ago
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What are the blank numbers for 16, 17, 18, and 19
Natasha_Volkova [10]

Answer:

16: 0.5, 5, 7.5

17: 62, 434, 682

18: 12.3, 62.5, 10

19: 1, 75, 300

Step-by-step explanation:

16: 9/18=0.5 so halve the numbers

17: 186/3=62 so multiply numbers by 62

18: 24.6/2= 12.3 so multiply by 12.3 and divide for the last one

19: 125/5=25 so for the first one divide by 25 and for the last two times by 25

8 0
2 years ago
The table shows some values of a function of the form y = ax2 + bx + c.
natali 33 [55]

Answer:

Value of constant term c is (-4)

Step-by-step explanation:

The given table represents a function which is in the form of a quadratic equation,

y = ax² + bx + c

We choose three points (3, -10), (4, -16) and (5, -24) from the table and satisfy the equation to get the values of a, b, and c.

For point (3, -10)

-10 = a(3)² + 3b + c

9a + 3b + c = -10 -------(1)

For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

(9a + 3b + c) - (16a + 4b + c) = -10 + 16

-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

(16a + 4b + c) - (25a + 5b + c) = -16 + 24

-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

-2a = 2

a = -1

From equation (4),

-7(1) + b = -6

b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

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