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scoundrel [369]
3 years ago
8

You are in the market for a used car and decide to visit a used car dealership. You know that the Blue Book value of the car you

are looking at is between $20,000 and $24,000. If you believe the dealer knows as much about the car as you do, how much are you willing to pay? Why? Assume that you care only about the expected value of the car you will buy and that the car values are symmetrically distributed.
Business
1 answer:
Artemon [7]3 years ago
3 0

Answer:

The expected value of the car you will buy is $22,000

Explanation:

In the given question, the car values are symmetrically distributed which means that we have to compute the mean between the values that are mentioned in the question.

So, the mean is an average of the numbers, the computation is shown below:

= (Value 1 + value 2) ÷ (number of observations)

= ($20,000 + $24,000) ÷ 2

= $22,000

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Question is incomplete. I will try to answer to the best of my ability.

Answer and Explanation:

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Similarly, 2/10, n/30 means 2% discount within 10 days since the transaction took place. Otherwise full payment after 10 day.

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Suppose you are a leader responsible for an organization’s vision/mission statements. How often do you think they should be chan
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Explanation:

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What is a broker?<br><br><br> Career Prep Edge
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3 years ago
Read 2 more answers
A liquid company produces hand sanitizer which has demand of 300,000 units per year.
jarptica [38.1K]

Answer:

EOQ =   =  15,491.93 units

Optimal order interval   18.8 days   (19.36  orders in year)

Total cost = $150,774.60

Explanation:

<em>The Economic Order Quantity (EOQ) is the order size that minimizes the balance of ordering cost and holding cost. At the EOQ, the carrying cost is equal to the holding cost.</em>

It is computed using he formulae below

EOQ = √ (2× Co× D)/Ch

<em>Co- ordering cost per order- 20, </em>

<em>Ch -Holding cost per unit per annum- 10%× $0.5=  0.05</em>

<em>Annual demand: D- 300,000</em>

EOQ = √(2× 20 * 2,580)/(10%× 0.5)

       =  15,491.93 units

Assuming 365 days, the optimal order interval in dates

Number of orders per year

= annual demand/EOQ

= 300,000/ 15,491.93

= 19.36 times

<u><em>in days:</em></u>

= EOQ/300,000 × 365 days

=   (15,491.93/ 300,000) × 365 days

= 18.8 days

Total annual cost =

<em>Total cost Purchase cost + Carrying cost + ordering cost </em>

                                                                                 $

Purchase cost = $0.5 × 300,000 =              150,000

Carrying cost = (15,491.93/2) * 10%*0.5 =       387.29

Ordering cost = (300,000/15,491.93 ) × 20 = <u>387.29</u>

Total cost                                                      1<u>50,774.60</u><u> </u>

       

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