Answer: the statement that is wrong about uncouplers is option A ( they allow ATP synthesis with no electron transport).
Explanation:
An uncoupler is a molecule that disrupts oxidative phosphorylation by dissociating the reactions of ATP synthesis from the electron transport chain. They allow electron transport without ATP synthesis. Their mechanism of action is basically to transport protons back into the matrix, preventing the required buildup of charge on the other side.
2,4-DNP is an example of an uncoupler.
Answer:
In one mole of NH₄Cl <em>6.022 × 10²³ atoms of N </em>are present.
Explanation:
Given data:
Number of atoms of N = ?
Number of moles of NH₄Cl = 1 mol
Solution:
First we have to calculate the number of atoms in NH₄Cl .
There is only 1 mole of N in 1 mole of NH₄Cl .
Now we will calculate the number of atoms of nitrogen in one mole of N by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole of N = 6.022 × 10²³ atoms of N
Thus in one mole of NH₄Cl 6.022 × 10²³ atoms of N are present.
The answer is mass
Hope this helps! :3
<span>B)<span>C2H6O<span>2
</span></span></span>
First, convert each percentage to grams: 38.7g, 9.70g, and 51.6g.
Next, calculate the number of moles of each element, based on the number of grams given.
C = 3.23 mol
H = 8.91 mol
O = 3.23 mol
Set up the ratio of moles of each element:
C3.34H9.70O3.23. Convert the decimals to whole numbers by dividing by the smallest subscript, 3.23.
The empirical formula is CH3O.
Now, compute the formula mass, which is 31. Finally, divide the molecular mass by the formula mass, 62/31 = 2. Multiple the subscripts by 2 to get the molecular formula.
<h3>Answer:</h3><h3>1865.5g</h3><h3>Explanation:</h3><h3 /><h2> first the chemical formular for ammonium hydroxide is NH4OH</h2><h3>its molarmass is given as N=14H=1O=16 </h3><h3> so we have 14 +1(2) +16+1 =35</h3><h2>also no of moles = mass / molarmass</h2><h3> we have 5.33×10 = mass/35 </h3><h2>therefore mass = 35 ×5.33×10 = 1865.5g</h2>