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Alexandra [31]
3 years ago
15

In the rate law, k is a universal constant. True or False? ( I have more questions on profile)

Chemistry
1 answer:
OverLord2011 [107]3 years ago
7 0
False information.....
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Why doesn’t vegetable oil stay dissolved in vinegar to make a salad dressing?
allsm [11]
In order for things to dissolve they must dissolve in a solvent similar to them (polar and polar or nonpolar and nonpolar) Oil is nonpolar and vinegar is polar therefore oil wont dissolve in vinegar
4 0
3 years ago
Read 2 more answers
What needs to happen for the equation CH4 + O2 → CO2 + H2O to be balanced?
worty [1.4K]
B. This is because the Hydrogen and Oxygen need balanced out.

Current-

C-1            |        C-1
H-4            |         H-2
O-2            |         O-3


Adding a coefficient of 2 before oxygen in the reactants and H2O in the products would balance this equation

<span>CH4 + 2O2 → CO2 + 2H2O</span>
C-1            |        C-1
H-4            |         H-4
O-4            |        O-4


4 0
4 years ago
Why is petroleum called liquid gold?
lana66690 [7]

Answer:

It is called liquid gold because of its high price and value and its economic need by all the countries worldwide.

Explanation:

Petroleum is present in abundant quantity in the some regions . So it is considered as Liquid gold, which they value a lot.

3 0
3 years ago
the equilibrium concentration of hydroxide ion in a saturated iron(ii) hydroxide solution is 1.2 x 10^-5 M at a certain temperat
Anit [1.1K]

From the calculation as shpwn in the procedure below, the equilibrium constant of the substance is 6.9 * 10^-15.

<h3>What is equilibrium constant?</h3>

The equilibrium constant for the solubility of aa solid in solution is called the solubility product Ksp. The Ksp shows the extent to which a solid is dissolved in solution.

Given that;

Fe(OH)2 ⇄Fe^2+ + 2(OH)^-

Ksp = s(2s)^2

We have s as 1.2 x 10^-5 M

So

Ksp = 4s^3

Ksp = 4( 1.2 x 10^-5 )^3

Ksp = 6.9 * 10^-15

Learn more about Ksp:brainly.com/question/27132799

#SPJ1

8 0
2 years ago
A soccer player applies a force of 56.6 N to a soccer ball while kicking it. If the ball has a mass of 0.46 kg, what is the acce
lubasha [3.4K]

Answer:

a=123.04\ m/s^2

Explanation:

Given that,

Force applied to a soccer player, F = 56.6 N

The mass of the ball, m = 0.46 kg

We need to find the acceleration of the soccer ball. The force acting on the ball is given by :

F = ma

Where

a is the acceleration

a=\dfrac{F}{m}\\\\a=\dfrac{56.6 }{0.46 }\\\\a=123.04\ m/s^2

So, the required solution is 123.04\ m/s^2.

3 0
3 years ago
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