Answer:
Explanation:En la tabla periódica los elementos están ordenados de forma que aquellos con propiedades químicas semejantes, se encuentren situados cerca uno de otro. Los elementos se distribuyen en filas horizontales, llamadas períodos.
Answer: The pH at equivalence point for the given solution is 5.59.
Explanation:
At the equivalence point,

So, first we will calculate the moles of
as follows.
= 0.0845 mol
Now, volume of
present will be calculated as follows.
Volume = 
= 
= 0.1891 L
Therefore, the total volume will be the sum of the given volumes as follows.
110 ml + 189.1 ml
= 299.13 ml
or, = 0.2991 L
Now, ![[CH_{3}NH_{3}^{+}] = \frac{0.0845 mol}{0.2991 L}](https://tex.z-dn.net/?f=%5BCH_%7B3%7DNH_%7B3%7D%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B0.0845%20mol%7D%7B0.2991%20L%7D)
= 0.283 M
Chemical equation for this reaction is as follows.

As,
= 
= 
Now, ![[HNO_{3}] = \sqrt{k_{a}[CH_{3}NH_{3}^{+}]}](https://tex.z-dn.net/?f=%5BHNO_%7B3%7D%5D%20%3D%20%5Csqrt%7Bk_%7Ba%7D%5BCH_%7B3%7DNH_%7B3%7D%5E%7B%2B%7D%5D%7D)
= 
= 
Now, pH will be calculated as follows.
pH = ![-log [H_{3}O^{+}]](https://tex.z-dn.net/?f=-log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
= 
= 5.59
Thus, we can conclude that pH at equivalence point for the given solution is 5.59.
Answer:
"1 M" will be the right solution.
Explanation:
The given values are:
Number of moles,
= 2 moles
Volume of solution,
= 2000 mL
or,
= 2 L
Now,
The molarity of the solution will be:
= 
On substituting the values, we get
= 
= 