Question

How many grams of sodium metal are needed to make 29.3 grams of sodium chloride? given the reaction: 2na + cl2 → 2nacl?

Answer 1

2Na + Cl2 → 2NaCl
46 g. ➡️ 117 g
x. ➡️ 29.3 g
$x = \frac{46 \times 29.3}{117} \\ x = 11.5 \: g$

Answer 2

Answer:

11.52 grams of sodium

Explanation:

The balanced equation is :

$2Na+Cl_{2}-->2NaCl$

As per balanced equation, two moles of sodium will give two moles of sodium chloride.

the molar mass of sodium chloride = atomic mass of Na + atomic mass of Cl

The molar mass of sodium chloride = 23 +35.5 = 58.5

thus for 58.5 grams of sodium chloride the mass of sodium required = 23 g

For one gram of sodium chloride the mass of sodium required = $\frac{23}{58.5}=0.393g$

Therefore for 29.3 grams of sodium chloride = 29.3x0.393  g of sodium = 11.52g