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kifflom [539]
3 years ago
10

How many grams of sodium metal are needed to make 29.3 grams of sodium chloride? given the reaction: 2na + cl2 → 2nacl?

Chemistry
2 answers:
Bess [88]3 years ago
5 0
2Na + Cl2 → 2NaCl
46 g. ➡️ 117 g
x. ➡️ 29.3 g
x =  \frac{46 \times 29.3}{117}  \\ x = 11.5 \: g
GaryK [48]3 years ago
5 0

Answer:

11.52 grams of sodium

Explanation:

The balanced equation is :

2Na+Cl_{2}-->2NaCl

As per balanced equation, two moles of sodium will give two moles of sodium chloride.

the molar mass of sodium chloride = atomic mass of Na + atomic mass of Cl

The molar mass of sodium chloride = 23 +35.5 = 58.5

thus for 58.5 grams of sodium chloride the mass of sodium required = 23 g

For one gram of sodium chloride the mass of sodium required = \frac{23}{58.5}=0.393g

Therefore for 29.3 grams of sodium chloride = 29.3x0.393  g of sodium = 11.52g

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<u>Answer:</u>

Atoms tend to gain or lose of shares electron in order to get 8 electrons in the outer shell which is called as Octet Rule. “Octa” means 8.

All atoms except noble gases have less than 8 electrons in its outer shell.

These atoms are unstable.

To attain stability atoms either gains or losses or shares electron to get 8 electrons in its outer shell.

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First chlorine shares its electron with the second one to make it get 8 electrons in its outer shell.

Same way second chlorine shares its electron with the second one to make it get 8 electrons in its outer shell

Each chlorine shares one of its electron with the other to make the other atom to get 8 electrons in  the outer shell.

Oxygen contains 6 electrons in its outer shell. Each Oxygen atom shares two of its electron with the other oxygen atom to make it get 8 in the outer shell.

Having 8 electrons in the outer shell makes the atom stable. Thats why atoms either gains or loss or shares electrons to get 8 electrons in the outer shell.

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